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a ) 100-7(x-5)=58
=> 7(x-5)=42
=.> x-5 = 6
=> x=11
180-5(x+1)=30
=> 5(x+1)=150
=> x+1=30\
=> x=29
6x-5=613
=> 6x=618
=> x=103
a) \(100-7\left(x-5\right)=58\)
\(\Leftrightarrow7\left(x-5\right)=42\)
\(\Leftrightarrow x-5=6\)
\(\Leftrightarrow x=11\)
b) \(180-5\left(x+1\right)=30\)
\(\Leftrightarrow5\left(x+1\right)=150\)
\(\Leftrightarrow x+1=30\)
\(\Leftrightarrow x=29\)
c) \(6x-5=613\)
\(\Leftrightarrow6x=618\)
\(\Leftrightarrow x=103\)
Ta có :
6x = 3x+1-5x+6x-5x+4x-9x+7x
=> 6x+1 = (3x+7x) - (5x+5x) + (6x+4x) - 9x
=> 6x+9x+1 = 10x - 10x + 10x
=> 15x+1 = 10x
=> 10x-15x = 1
=> -5x = 1
=> x = 1 : (-5)
=> x = -1
Vậy x = -1
5x+6x+1=56
<=>5x+6x=56-1
<=>5x+6x=55
<=>x(5+6)=55
<=>x.11=55
<=>x=55:11
<=>x=5
Vậy x=...
6x+1=13
<=>6x=13-1
<=>6x=12
<=>x=12:6
<=>x=2
Vậy x=...
~hok tốt~
k mik nhé
\(5x+6x+1=56\Leftrightarrow5x+6x=56-1\Leftrightarrow5x+6x=55\)
\(\Leftrightarrow\left(5+6\right)x=55\Leftrightarrow11x=55\Leftrightarrow x=55:11\)
\(\Rightarrow x=5\)
\(6x+1=13\Leftrightarrow6x=13-1\Leftrightarrow6x=12\)
\(\Leftrightarrow x=12:6\)
\(\Leftrightarrow x=2\)
q, bạn ghi đề rõ nhé
s, \(\dfrac{2}{3}x=\dfrac{1}{2}-\dfrac{7}{12}=\dfrac{-1}{12}\Leftrightarrow x=-\dfrac{1}{12}:\dfrac{2}{3}=-\dfrac{3}{24}=-\dfrac{1}{8}\)
t, \(\dfrac{3}{4}x=\dfrac{1}{6}-\dfrac{1}{5}=\dfrac{-1}{30}\Leftrightarrow x=-\dfrac{1}{30}:\dfrac{3}{4}=-\dfrac{4}{90}=-\dfrac{2}{45}\)
u, \(\dfrac{1}{6}x=\dfrac{3}{8}-\dfrac{1}{4}=\dfrac{1}{8}\Leftrightarrow x=\dfrac{1}{8}:\dfrac{1}{6}=\dfrac{6}{8}=\dfrac{3}{4}\)
s, 23x=12−712=−112⇔x=−112:23=−324=−1823x=12−712=−112⇔x=−112:23=−324=−18
t, 34x=16−15=−130⇔x=−130:34=−490=−24534x=16−15=−130⇔x=−130:34=−490=−245
u, 16x=38−14=18⇔x=18:16=68=34
HT
\(6^x-6^{x-1}=180\)
\(\Rightarrow6^x\cdot1-6^x\cdot6^{-1}=180\)
\(\Rightarrow6^x\cdot\left(1-\dfrac{1}{6}\right)=180\)
\(\Rightarrow6^x\cdot\dfrac{5}{6}=180\)
\(\Rightarrow6^x=180:\dfrac{5}{6}\)
\(\Rightarrow6^x=216\)
\(\Rightarrow6^x=6^3\)
\(\Rightarrow x=3\)
x không tồn tại