\(105-\left(135-7x\right):9=97\\ \Rightarrow\left(135-7x\right):9=105-97\\ \Rightarrow\left(135-7x\right):9=8\\ \Rightarrow135-7x=8.9\\ \Rightarrow135-7x=72\\ \Rightarrow7x=135-72\\ \Rightarrow7x=63\\ \Rightarrow x=63:7\\ \Rightarrow x=9\)

=>(135-7x):9=8

=>135-7x=72

=>7x=63

hay x=9

Bài của bạn nhầm tiêu đề r 

ỤnU

\(565-13x=370\\ 13x=565-370=195\\x=\dfrac{195}{13}=15\)

\(105-\left(135-7x\right):9=97\\ \dfrac{135-7x}{9}=105-97=8\\ 135-7x=9.8=72\\ 7x=135-72=63\\ x=\dfrac{63}{7}=9\)

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a) 565 - 13.x = 370

13.x = 565 - 370

13.x = 195

x = 195 : 13

x = 15

b) 105 - (135 - 7x) : 9 = 97

(135 - 7x) : 9 = 105 - 97

(135 - 7x) : 9 = 8

135 - 7x = 8 x 9

135 - 7x = 72

7x = 135 - 72

7x = 63

x = 63 : 7

x = 9

a) 565 - 13.x = 370

13.x = 565 - 370

13.x = 195

x = 195 : 13

x = 15

b) 105 - (135 - 7x) : 9 = 97

(135 - 7x) : 9 = 105 - 97

(135 - 7x) : 9 = 8

135 - 7x = 8 x 9

135 - 7x = 72

7x = 135 - 72

7x = 63

x = 63 : 7

x = 9

cho like

e: =>x=0 hoặc x=1

a:565-13.x=30

13.x=565-370

13.x=195

x=195:13

x=15

Nếu sai sót gì thì e xin lỗi ạ ^^

Bài 2: 

a: =>x-1=1 hoặc x-1=-1

=>x=2 hoặc x=0

b: =>x+1=-1

hay x=-2

c: =>(135-7x):9=8

=>135-7x=72

=>7x=63

hay x=9

d: =>(x+7)(x-3)<0

=>-7<x<3

e: \(\Leftrightarrow3^{x-3}=18+9=27\)

=>x-3=3

hay x=6

f: =>4-2x=0

hay x=2

bài 1 ik

D

D. 135 - 9