575- [6x+70] = 445              315 +[125-x]  = 435              f 541+[218-x]=435

6x+70           =575-445         125-x            = 435- 315         218-x         = 541-435

6x+70           = 130               125-x           =120                 218-x          =106

6x                = 130-70           x                 = 125 - 120        x                = 218-106

6x                = 60                 x                  = 5                   x                =   112

x                 =  60:6

x                  = 10

bạn ơi khó hiểu quá,.,.,.

\(\orbr{\begin{cases}\\\end{cases}}\)

a) cách 1 :

\(-5\left(32-36\right)+\left(31-39\right)=-5.\left(-4\right)+\left(-8\right)=12\)

cách 2 ;

\(-5\left(32-36\right)+\left(31-39\right)=-5.32-\left(-5.36\right)+\left(-8\right)=-160-\left(-180\right)+8=12\)

b) cách 1 

\(-2\left(15-27\right)-4\left(12-8\right)=-2.\left(-12\right)-4.4=24-16=8\)

cách 2:

\(-2\left(15-27\right)-4\left(12-8\right)=-2.15-\left(-2.27\right)-4.12-4.\left(8\right)=-30-\left(-54\right)-48-\left(-32\right)=8\)

c) \(36:4-2x=3\)

           \(9-2x=3\)

                     \(2x=6\)

                        \(x=3\)

Vậy x=3

d) \(\left(3x-15\right).2=20\)

\(3x-15=10\)

\(3x=45\)

\(x=15\)

Vẫy=15

c) ( 36 : 4 ) - 2x = 3

9 - 2x = 3

2x = 6 

x = 3

d) ( 3x - 15 ) . 2 = 20

3x - 15 = 10

3x = 25

x = 25/3

a) \(3^x-2=5^2\)

\(\Rightarrow3^x-2=25\)

\(\Rightarrow3^x=27\)

\(\Rightarrow3^x=3^3\)

\(\Rightarrow x=3\)

b) \(\left(x+1\right)^2=36\)

\(\Rightarrow\left(x+1\right)^2=6^2\)

\(\Rightarrow x+1=6\)

\(\Rightarrow x=5\)

c) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)

\(\Rightarrow\left(2x-15\right)^5:\left(2x-15\right)^3=1\)

\(\Rightarrow\left(2x-15\right)^2=1\)

\(\Rightarrow2x-15=1\)

\(\Rightarrow2x=16\)

\(\Rightarrow x=16:2=8\)

Chúc em học tốt nhé!

a) \(3^x-2=5^2\)

\(\Rightarrow3^x-2=25\)

\(\Rightarrow3^x=27\)

\(\Rightarrow3^x=3^3\)

\(\Rightarrow x=3\)

b) \(\left(x+1\right)^2=36\)

\(\Rightarrow\left(x+1\right)^2=6^2\)

\(\Rightarrow x+1=6\)

\(\Rightarrow x=5\)

c) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)

\(\Rightarrow\left(2x-15\right)^5:\left(2x-15\right)^3=1\)

\(\Rightarrow\left(2x-15\right)^2=1\)

\(\Rightarrow\left(2x-15\right)^2=1^2\)

\(\Rightarrow2x-15=1\)

\(\Rightarrow2x=16\)

\(\Rightarrow x=8\)

Chúc em học tốt nhé!

x^3=125

x=5

x⁶:x³=125

x^6-3=125

x³=125

x³=5³

x=5

vậy x=5

xy+ 3y=15

(x+3)y=15

=> x+3;y thuộc Ư(15)

Ta có bảng:

Vậy.......................................................

(2x - 3)² = 36

(2x - 3)² = 6²

* 2x-3=6                        * 2x-3=-6

  2x=9                              2x=-3

    x=\(\frac{9}{2}\)                         x=\(\frac{-3}{2}\)

Vậy....................................................

(2x – 1)³ = -8.

(2x - 1 )³ = (-2)³

 2x - 1 = -2

 2x = -2 + 1

 2x = -1

   x = \(\frac{-1}{2}\)

vậy........................

sorry ban

a) Ta có: \(2-\left(15+2x\right)=-5\)

\(\Leftrightarrow2-15-2x+5=0\)

\(\Leftrightarrow-2x-8=0\)

\(\Leftrightarrow-2x=8\)

\(\Leftrightarrow x=-4\)

Vậy: x=-4

b) Ta có: \(\left(x-3\right)^3=-27\)

\(\Leftrightarrow x-3=-3\)

hay x=0

Vậy: x=0

c) Ta có: \(\left(x+1\right)^2=36\)

\(\Leftrightarrow\left[{}\begin{matrix}x+1=6\\x+1=-6\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-7\end{matrix}\right.\)

Vậy: x∈{5;-7}

d) Ta có: \(2x-\left(x+5\right)=1-x\)

\(\Leftrightarrow2x-x-5-1+x=0\)

\(\Leftrightarrow2x-6=0\)

\(\Leftrightarrow2x=6\)

hay x=3

Vậy: x=3

e) Ta có: \(15-\left(-3x+13\right)=2\left(x+1\right)\)

\(\Leftrightarrow15+3x-13-2x-2=0\)

\(\Leftrightarrow x=0\)

Vậy: x=0

Thế bạn có biết \(-27=\left(-3\right)^3\) không?

3x + 18 = 3⁶ : 3³

=> 3x + 18 = 3³

=> 3x + 18 = 27

=> 3x = 9

=> x = 3

b) 3x+18=3⁶:3³

3x+18=3^6-3

3x+18=3³

3x+18=27

3x=27-18

3x=9

x=9:3

x=3

c) (2x-15)⁵=(2x-15)³

Ta có:2x-15=2x-15

5 không bằng 3

=> không có giá trị x nào

d) 3.(2.x-6)+36=2².3²

3.(2.x-6)+36=4.9

3.(2.x-6)+36=36

3.(.2.x-6)=36-36

3.(2.x-6)=0

2.x-6=0:3

2.x-6=0

2.x=0+6

2.x=6

x=6:2

x=3

Bài này tự làm