Yx4=0x6 tìm y
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
219,1 + y:y < y \(\times\) 2 + y \(\times\) 4 - y < 230,2 - y + y
219,1 + 1 < y \(\times\) 2 + y \(\times\) 4 - y \(\times\) 1 < 230,2 - ( y - y)
210,1 < y \(\times\) ( 2 + 4 - 1) < 230,2
210,1 < y \(\times\) 5 < 230,2
210,1 : 5 < y < 230,2: 5
42,02 < y < 46,04
y * 1 + y * 2 + y * 3 + y * 4 + y *1 = 825
y * ( 1 + 2 + 3 + 4 + 1) =825
y * 11 = 825
y = 825 / 11
y = 75
\(x^2y-xz+z-y\\ =\left(x^2y-y\right)-\left(xz-z\right)\\ =y\left(x^2-1\right)-z\left(x-1\right)\\ =y\left(x-1\right)\left(x-1\right)-z\left(x-1\right)\\ =\left(x-1\right)\left(y\left(x-1\right)-z\right)\\ =\left(x-1\right)\left(xy-y-z\right)\)
\(x^4-x^3+x^2-1\\ =x^3\left(x-1\right)+\left(x-1\right)\left(x+1\right)\\ =\left(x-1\right)\left(x^3+x+1\right)\)
\(x^2y-xz+z-y\)
\(=\left(x^2y-y\right)-\left(xz-z\right)\)
\(=y\left(x^2-1\right)-z\left(x-1\right)\)
\(=y\left(x+1\right)\left(x-1\right)-z\left(x-1\right)\)
\(=\left(x-1\right)\left[y\left(x+1\right)-z\right]\)
\(=\left(x-1\right)\left(xy+y-z\right)\)
\(------\)
\(x^4-x^3+x^2-1\)
\(=\left(x^4-x^3\right)+\left(x^2-1\right)\)
\(=x^3\left(x-1\right)+\left(x-1\right)\left(x+1\right)\)
\(=\left(x-1\right)\left(x^3+x+1\right)\)
y*4=0*6
=>y*4=0
=>x=0:4
=>x=0
Vậy x=0
y x 4 = 0 x 6
y x 4 = 0
y = 0 : 4
y = \(\varnothing\)