1/5+1/14+1/28+1/44+1/61+1/85+1/97 =0,3683

1/2 = 0,5

0,3683<0,5 nên 1/5+1/14+1/28+1/44+1/61+1/85+1/97 < 1/2

Ta có \(\frac{1}{5}+\frac{1}{14}+\frac{1}{28}+\frac{1}{44}+\frac{1}{61}+\frac{1}{85}+\frac{1}{97}>\frac{1}{14}+\frac{1}{14}+\frac{1}{14}+\frac{1}{14}+\frac{1}{14}+\frac{1}{14}+\frac{1}{14}=\frac{1}{2}\)

                                                                                                 \(>\frac{1}{2}\)

mình có làm tắt mấy bước nhé

Đặt 1/5 + 1/14+1/28 +1/44 + 1/61+1/85+1/97 =A
Ta có : A = 1/5 + ( 1/14+1/28+1/44)+(1/61+1/85+1/97)
A < 1/5 ( 1/14.3)+(1/61.3)
A < 1/5+ 3/14+3/61
A < 1/5 + 3/12+1/20
A < 1/5+1/4+1/20
A < 1/2 ( đpcm)

Cho mik hỏi là 1/97 hay 1/91 vậy

Sai đề. Sửa đề :v

Cmr: \(\dfrac{1}{5}+\dfrac{1}{14}+\dfrac{1}{28}+\dfrac{1}{44}+\dfrac{1}{61}+\dfrac{1}{85}+\dfrac{1}{97}< \dfrac{1}{2}\)

Giải:

Đặt \(A=\dfrac{1}{5}+\dfrac{1}{14}+\dfrac{1}{28}+\dfrac{1}{44}+\dfrac{1}{61}+\dfrac{1}{85}+\dfrac{1}{97}\)

Ta có:

\(A=\dfrac{1}{5}+\left(\dfrac{1}{14}+\dfrac{1}{28}+\dfrac{1}{44}\right)+\left(\dfrac{1}{61}+\dfrac{1}{85}+\dfrac{1}{97}\right)\)

\(A< \dfrac{1}{5}\left(\dfrac{1}{14.3}\right)+\left(\dfrac{1}{61.3}\right)\)

\(A< \dfrac{1}{5}+\dfrac{3}{14}+\dfrac{3}{61}\)

\(A< \dfrac{1}{5}+\dfrac{3}{12}+\dfrac{1}{20}\)

\(A< \dfrac{1}{5}+\dfrac{1}{4}+\dfrac{1}{20}\)

\(\Rightarrow A< \dfrac{1}{2}\)

Vậy \(\dfrac{1}{5}+\dfrac{1}{14}+\dfrac{1}{28}+\dfrac{1}{44}+\dfrac{1}{61}+\dfrac{1}{85}+\dfrac{1}{97}< \dfrac{1}{2}\) \((đpcm)\)

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