So sánh các phân số sau
a: 12/49 và 13/47 c: 19/31 và 17/35
b: 64/-83 và 73/81 d: 67/77 và 73/83
e: 456/461 và 123/128
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12/49 > 13/47
64/85 > 73/81
19/31 > 17/35
67/77 > 73/83
a) \(\frac{67}{77}=1-\frac{10}{77};\frac{73}{83}=1-\frac{10}{83}\)
Vì \(\frac{10}{77}>\frac{10}{83}\) nên \(1-\frac{10}{77}
a) 12 < 13; 49 > 47 => 12/49 < 13/47
b) 64 < 73; 85 > 81 => 64/85 < 73/81
c) 19 > 17; 31 < 35 => 19/31 > 17/35
d) 67/77 = 1 - 10/77; 73/83 = 1- 10/83. Mà 10/77 > 10/83 => 67/77 < 73/83.
e) 456/461 = 1 - 5/461; 123/128 = 1 - 5/128. Mà 5/461 < 5/128 => 456/461 > 123/128.
f) 149/157 = 1 - 8/157; 449/458 = 1 - 9/458. Mà 8/157 = 16/314 > 9/458 => 149/157 < 449/458.
\(\dfrac{12}{49}=\dfrac{564}{2303};\dfrac{13}{47}=\dfrac{637}{2303}\)
Vì 564<637=>\(\dfrac{564}{2303}< \dfrac{637}{2303}\)=>\(\dfrac{12}{49}< \dfrac{13}{47}\)
a)\(12< 13;49>47\)
\(\Rightarrow\dfrac{12}{49}< \dfrac{13}{47}\)
b)\(\dfrac{64}{85}>\dfrac{43}{85}\Rightarrow\dfrac{64}{85}>\dfrac{1}{2}\)
\(\dfrac{17}{35}< \dfrac{17}{34}\Rightarrow\dfrac{17}{35}< \dfrac{1}{2}\)
\(\Rightarrow\dfrac{17}{35}< \dfrac{64}{85}\)
c) \(\dfrac{19}{31}>\dfrac{16}{31}\Rightarrow\dfrac{19}{31}>\dfrac{1}{2}\)
\(\dfrac{17}{35}< \dfrac{17}{34}\Rightarrow\dfrac{17}{35}< \dfrac{1}{2}\)
\(\Rightarrow\dfrac{17}{35}< \dfrac{19}{31}\)
d)
\(1-\dfrac{67}{77}=\dfrac{10}{77}\)
\(1-\dfrac{73}{83}=\dfrac{10}{83}\)
\(\dfrac{10}{77}>\dfrac{10}{83}\Rightarrow\dfrac{67}{77}< \dfrac{73}{83}\)
e)\(1-\dfrac{456}{461}=\dfrac{5}{461}\)
\(1-\dfrac{123}{128}=\dfrac{5}{128}\)
\(\dfrac{5}{461}< \dfrac{5}{128}\Rightarrow\dfrac{456}{461}>\dfrac{123}{128}\)
\(a,\dfrac{12}{49}< \dfrac{12}{47}< \dfrac{13}{47}\Rightarrow\dfrac{12}{49}< \dfrac{12}{47}\)
b, Ta có: \(\dfrac{17}{35}=\dfrac{51}{105}\)
\(\dfrac{64}{85}>\dfrac{64}{105}>\dfrac{51}{105}\Rightarrow\dfrac{64}{85}>\dfrac{51}{105}\) hay \(\dfrac{64}{85}>\dfrac{17}{85}\)
c,\(\dfrac{19}{31}>\dfrac{17}{31}>\dfrac{17}{35}\Rightarrow\dfrac{19}{31}>\dfrac{17}{35}\)
d, \(\dfrac{67}{77}+\dfrac{10}{77}=1\)
\(\dfrac{73}{83}+\dfrac{10}{83}=1\)
\(\dfrac{10}{77}>\dfrac{10}{83}\Rightarrow\dfrac{67}{77}< \dfrac{73}{83}\)
e, \(\dfrac{456}{461}+\dfrac{5}{461}=1\)
\(\dfrac{123}{128}+\dfrac{5}{128}=1\)
\(\dfrac{5}{461}< \dfrac{5}{128}\Rightarrow\dfrac{456}{461}>\dfrac{123}{128}\)