A=\(\frac{65+891+135+909}{731-47+69-253}\)
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\(A=\frac{65+891+135+909}{731-47+69-253}\)
\(A=\frac{65+135+891+909}{731+69-47-253}\)
\(A=\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}\)
\(A=\frac{200+1800}{800-300}\)
\(A=\frac{2000}{500}=4\)
A = \(\frac{65+891+135+909}{731-47+69-253}\)
A = \(\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}\)
A = \(\frac{200+1800}{800-300}\)
A = \(\frac{2000}{500}\)
A = 4
\(C=\frac{65+891+135+909}{731-47+69-253}\)
\(C=\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}\)
\(C=\frac{200+1800}{800-300}\)
\(C=\frac{2000}{500}=4\)
\(A=\frac{595959}{454545}-\frac{14141414}{15151515}\)
\(A=\frac{595959:10101}{454545:10101}-\frac{14141414:1010101}{15151515:1010101}\)
\(A=\frac{59}{45}-\frac{14}{15}\)
\(A=\frac{59}{45}-\frac{42}{45}=\frac{17}{45}\)
\(B=\frac{65+891+135+909}{731-47+69-253}\)
\(B=\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}\)
\(B=\frac{200+1800}{800-300}=\frac{2000}{500}=4\)
65+891+135+989/731-47+69-253 = (65+135) + (891+69) - 47 - 253 + 989 / 731
= 200 + 960 - 300 + 989/731
= 860 + 989/731
= 14643/17
a) 27.121-87.27+73.34
=27.(121-87)+73.34
=27.34+73.34
=34(27+73)
=34.100
=3400
b) 48.19+134.52+48.115
=48.19+48.115+134.52
=48(19+115)+134.52
=48.134+134.52
=134(48+52)
=134.100
=13400
c) 65+891+135+909/731-47+69-253
VT:(65+135)+(891+909)
=200+1800
=2000
VP:(731+69)-(253+47)
=800-300
=500
2000/500=4
d)18.123+9.4576.2+3.5310.6/1+4+7+..+55+58-410
VT:18.123+18.4567+18.5310
=18(123+4567+5310)
=18.10009
=18(10000+9)
=180000
VP:Tổng : 1+4+7+...+55+58
Có số số hạng là :
(58-1):3+1=20( số )
Tổng bằng : (58+1).20:2=590
590-410=180
180000:180=1000
Mình chữa câu d tí 9.4576.2 là sai ;;; 9.4567.2 mới đúng