a. -25

b. 0,25

a . ( 2,75 + 125% ) x 5/2 - 0,4 x 2 : 8%                           b . ( 1/3 - 25% ) : 50% + ( 1/3 + 0,25 ) x 1/7

  = ( 2,75 + 1,25 ) x 2,5 - 0,4 x 2 : 0,08                             = ( 1/3 - 1/4 ) : 1/2 + ( 1/3 + 1/4 ) x 1/7

  = 4 x 2,5 - 0,4 x 2 : 0,8                                                   = 1/12 : 1/2 + 1/12 x 1/7

  = 10 - 0,8 : 0,8                                                                = 1/12 x 2 + 1/12 x 1/7

  = 10 - 1                                                                           = 1/12 x ( 2 + 1/7 )

  = 9                                                                                  = 1/12 x 15/7 = 5/28

a)19,75×0,4×2,5

= 19,75×(0,4×2,5)

=19,75×1=19,75

c)9,67×80×1,25

=9,67×(80×1,25)

=9,67×10=96,7

b)49,6×0,5×4

=49,6×(0,5×4)

=49,6×0,2=9,92

bạn ơi còn thiếu ạ

a/x=3

b/11,43..........

c/x=30,52

d/1,125

bạn nguễn đăng khôi có thể làm có cả biểu thức a,b,c được ko

1. Kết quả (x+1/2)^2 =

A. x^2+2x+1/4

B. x^2-x+1/4

C. x^2+x+1/4

D. x^2+x+0,2-1/3x)(0,21/2

2. Kết quả (x^2+2y)^2 bằng

A. 1/4+4y^2

B. 1/4+4y+4y^2

C. 1/4+2y+4y^2

D. 1/4+2y+2y^2

3. Kết quả phép tính (1/2x-0,5)^2 là

A. 1/2x^2-1/2x+0,25

B. 1/4x^2-0,25

C. 1/2x^2-0,25x+0,5

D. 1/4x^2-0,5x+0,25

4. Kết quả (0,2-1/3x)(0,2+1/3x)

A. 1/2x^2-1/2x+0,25

B. 1/4x^2-0,25

C. 1/2x^2-0,5x+2,5

D. Tất cả đều sai

5. Viết dưới dạng bình phương tổng x^2+2x+1 là:

A. (x+2)^2

B. (x+1)^2

C. (2x+1)^2

D. Tất cả đều sai

6. Kết quả (100a+5)^2 bằng

A. 100a^2+100a+25

B. 100a+100a+25

C. 100a^2-100a+25

D. 100a-100a+25

7. Kết quả thực hiện phép tính (2x-1/3)^2

A. 8x^3-1/27

B. 8x^2-2x^2+2/3x-1/27

8. Kết quả (1/2x-3)^2 = \(\frac{1}{4}x^2-3x+9\)

9. Với x=6 giá trị của đa thứcx^3+12x^2+48x+64 là

A. 900

B. 1000

C. 3000

D. Khác

10. Khi phân tích đa thức x^2-x kết quả là

A. x^2-x=x+1

B. x^2-x=x(x-1)

C. x^2-x=x

D. x^2-x=x^2(x+1)

Bài 3: 

b: \(\Leftrightarrow x^2\left(x+1\right)^2=0\)

hay \(x\in\left\{0;-1\right\}\)

c: \(\Leftrightarrow\left(x-1\right)\left(x^2+x+1\right)=0\)

=>x-1=0

hay x=1

d: \(\Leftrightarrow6x^2-3x-4x+2=0\)

\(\Leftrightarrow\left(2x-1\right)\left(3x-2\right)=0\)

hay \(x\in\left\{\dfrac{1}{2};\dfrac{2}{3}\right\}\)

\(4,7\div0,25+5,3\times4\)

\(=18,8+21,2\)

\(=40\)

\(3\times\left(a-2\right)+150=240\)

\(3\times\left(a-2\right)=90\)

\(a-2=30\)

\(a=32\)

\(\dfrac{1}{9}+a+\dfrac{7}{12}=\dfrac{17}{18}\)

\(\dfrac{1}{9}+a=\dfrac{13}{36}\)

\(a=\dfrac{1}{4}\)

\(\left(\dfrac{1}{2}\times\dfrac{1}{3}+\dfrac{1}{3}\times\dfrac{1}{4}+\dfrac{1}{4}\times\dfrac{1}{5}+\dfrac{1}{5}\times\dfrac{1}{6}+\dfrac{1}{6}\times\dfrac{1}{7}+\dfrac{1}{7}\times\dfrac{1}{8}\right)\times a=\dfrac{9}{16}\)

\(\left(\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+\dfrac{1}{4\times5}+\dfrac{1}{5\times6}+\dfrac{1}{6\times7}+\dfrac{1}{7\times8}\right)\times a=\dfrac{9}{16}\)

\(\left(\dfrac{1}{2}-\dfrac{1}{8}\right)\times a=\dfrac{9}{16}\)

\(\dfrac{3}{8}\times a=\dfrac{9}{16}\)

\(a=\dfrac{3}{2}\)

\(\frac{3}{4}+\frac{1}{4}\cdot x+x-\frac{7}{6}\cdot x=\frac{5}{12}\)

\(\frac{3}{4}+\frac{1}{4}\cdot x-\frac{7}{6}\cdot x+x\cdot1=\frac{5}{12}\)

\(\frac{3}{4}+x\left(\frac{1}{4}-\frac{7}{6}+1\right)=\frac{5}{12}\)

\(\frac{3}{4}+x\cdot\frac{1}{12}=\frac{5}{12}\)

\(x\cdot\frac{1}{12}=\frac{5}{12}-\frac{3}{4}\)

\(x\cdot\frac{1}{12}=\frac{5}{12}-\frac{9}{12}\)

\(x\cdot\frac{1}{12}=\frac{-1}{3}\)

\(x=\frac{-1}{3}\text{ : }\frac{1}{12}\)

\(x=\frac{-1}{3}\cdot12\)

\(x=\frac{-12}{3}\)

\(x=-4\)

\(\text{b, }0,25\cdot x-\frac{2}{3}\cdot x=-1\frac{1}{6}\)

\(\frac{1}{4}\cdot x-\frac{2}{3}\cdot x=\frac{-7}{6}\)

\(x\cdot\left(\frac{1}{4}-\frac{2}{3}\right)=\frac{-7}{6}\)

\(x\cdot\frac{-5}{12}=\frac{-7}{6}\)

\(x=\frac{-7}{6}\text{ : }\frac{-5}{12}\)

\(x=\frac{-7}{6}\cdot\frac{12}{-5}\)

\(x=\frac{-14}{-5}\)

a) Ta có: \(7-\left(2x+4\right)=-\left(x+4\right)\)

\(\Leftrightarrow7-2x-4=-x-4\)

\(\Leftrightarrow-2x+3+x+4=0\)

\(\Leftrightarrow-x+7=0\)

\(\Leftrightarrow-x=-7\)

hay x=7

Vậy: S={7}

b) Ta có: \(\dfrac{2+x}{5}-0.5x=\dfrac{1-2x}{4}+0.25\)

\(\Leftrightarrow\dfrac{4\left(2+x\right)}{20}-\dfrac{0.5x\cdot20}{20}=\dfrac{5\left(1-2x\right)}{20}+\dfrac{20\cdot0.25}{20}\)

\(\Leftrightarrow4\left(2+x\right)-10x=5\left(1-2x\right)+5\)

\(\Leftrightarrow8+4x-10x=5-10x+5\)

\(\Leftrightarrow-6x+8=-10x+10\)

\(\Leftrightarrow-6x+8+10x-10=0\)

\(\Leftrightarrow4x-2=0\)

\(\Leftrightarrow4x=2\)

hay \(x=\dfrac{1}{2}\)

Vậy: \(S=\left\{\dfrac{1}{2}\right\}\)

d) Ta có: \(\dfrac{x-1}{59}+\dfrac{x-2}{58}+\dfrac{x-3}{57}=\dfrac{x-59}{1}+\dfrac{x-58}{2}+\dfrac{x-57}{3}\)

\(\Leftrightarrow\dfrac{x-1}{59}-1+\dfrac{x-2}{58}-1+\dfrac{x-3}{57}-1=\dfrac{x-59}{1}-1+\dfrac{x-58}{2}-1+\dfrac{x-57}{3}-1\)

\(\Leftrightarrow\dfrac{x-60}{59}+\dfrac{x-60}{58}+\dfrac{x-60}{57}=\dfrac{x-60}{1}+\dfrac{x-60}{2}+\dfrac{x-60}{3}\)

\(\Leftrightarrow\left(x-60\right)\left(\dfrac{1}{59}+\dfrac{1}{58}+\dfrac{1}{57}\right)-\left(x-60\right)\left(1+\dfrac{1}{2}+\dfrac{1}{3}\right)=0\)

\(\Leftrightarrow\left(x-60\right)\left(\dfrac{1}{59}+\dfrac{1}{58}+\dfrac{1}{57}-1-\dfrac{1}{2}-\dfrac{1}{3}\right)=0\)

mà \(\dfrac{1}{59}+\dfrac{1}{58}+\dfrac{1}{57}-1-\dfrac{1}{2}-\dfrac{1}{3}\ne0\)

nên x-60=0

hay x=60

Vậy: S={60}