\(\left(x:23+45\right).67=8911\)

\(x:23+45=8911:67\)

\(x:23+45=133\)

\(x :23=133-45\)

\(x:23=88\)

\(x=88.23\)

\(x=2024\)

thiếu đề b1
 

Nhanh lên nhé các bạn ai nhanh nhất mình sẽ cho 1 k

Giúp mình nha mình đang cần gấp

`123-x=38`

`=> x= 123-38`

`=>x=85`

Vậy `x=85`

__

`(x+15) -7=33`

`=>x+15=33+7`

`=>x+16= 40`

`=>x=40-16`

`=>x=24`

Vậy `x=24`

__

`3^(x+3) -13=230`

`=> 3^(x+3) = 230+13`

`=>3^(x+3)=243`

`=> 3^(x+3)=3^5`

`=> x+3=5`

`=>x=5-3`

`=>x=2`

Vậy `x=2`

X x 99 + X = 300
\(\Rightarrow\)X x 100 = 300
\(\Rightarrow\)X = 3
X x 123 - 245 = 7012
\(\Rightarrow\)X x 123 = 7257
\(\Rightarrow\)X = 7257 : 123
\(\Rightarrow\)X = 59
X x 124 - 2568 = 5988
\(\Rightarrow\)X x 124 = 8556
\(\Rightarrow\)X = 8556 : 124
\(\Rightarrow\)X = 69

X x 99 + X = 300

X x ( 99 + 1 ) = 300

X x 100 = 300

        X = 300 : 100

        X = 3

X x 123 - 245 = 7012

X x 123 = 7012 + 245

X x 123 = 7257

          X = 7257 : 123

          X = 59

X x 124 - 2568 = 5988

X x 124 = 5988 + 2568

X x 124 = 8556

          X = 8556 : 124

          X = 69

Tìm x thuoc z:

1) \(26-\left|x+9\right|=-13\)

\(\Leftrightarrow\left|x+9\right|=26-\left(-13\right)\)

\(\Leftrightarrow\left|x+9\right|=39\)

\(\Leftrightarrow\left[{}\begin{matrix}x+9=39\\x+9=-39\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=39-9=30\\x=-39-9=-48\end{matrix}\right.\)

Vậy: \(x\in\left\{30;-48\right\}\)

2) \(\left|x+7\right|-13=25\)

\(\Leftrightarrow\left|x+7\right|=25+13=38\)

\(\Leftrightarrow x+7\in\left\{38;-38\right\}\)

\(\Leftrightarrow x\in\left\{31;-45\right\}\)

Vậy:.................

tim x biet

\(1)123-3.\left(x+4\right)=23\)

\(\Leftrightarrow3\left(x+4\right)=123-23\)

\(\Leftrightarrow3\left(x+4\right)=100\)

\(\Leftrightarrow x+4=\frac{100}{3}\)

\(\Leftrightarrow x=\frac{100}{3}-4=\frac{100-12}{3}=\frac{88}{3}\)

Vậy:................

2) Tương tự

Ko bt làm