Tính bằng cách thuận tiện nhất:
(1+1/2)*(1+1/3)*(1+1/4)
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\(\frac{5}{11}.\frac{7}{25}+\frac{15}{11}.\frac{1}{5}\)
\(=\frac{5}{11}.\frac{7}{25}+\frac{5}{11}.3.\frac{1}{5}\)
\(=\frac{5}{11}.\frac{7}{25}+\frac{5}{11}.\frac{3}{5}\)
\(=\frac{5}{11}\left(\frac{7}{25}+\frac{3}{5}\right)\)
\(=\frac{5}{11}\left(\frac{7}{25}+\frac{15}{25}\right)\)
\(=\frac{5}{11}.\frac{22}{25}=\frac{2}{5}\)
\(a.\left(\dfrac{2}{5}.\dfrac{5}{2}\right).\dfrac{10}{21}=1.\dfrac{10}{21}=\dfrac{10}{21}\)
\(\dfrac{1}{2}.4+\dfrac{3}{4}.4=2+3=5\)
a; 5\(\dfrac{3}{4}\) : 3 + 2\(\dfrac{1}{4}\).\(\dfrac{1}{3}\) - \(\dfrac{3}{8}\)
= \(\dfrac{23}{4}\) : 3 + \(\dfrac{9}{4}\).\(\dfrac{1}{3}\) - \(\dfrac{3}{8}\)
= \(\dfrac{23}{4}\) x \(\dfrac{1}{3}\) + \(\dfrac{3}{4}\) - \(\dfrac{3}{8}\)
= \(\dfrac{23}{12}\) + \(\dfrac{3}{4}\) - \(\dfrac{3}{8}\)
= \(\dfrac{46}{24}\) + \(\dfrac{18}{24}\) - \(\dfrac{9}{24}\)
= \(\dfrac{64}{24}\) - \(\dfrac{9}{24}\)
= \(\dfrac{55}{24}\)
a) Ta có: \(\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right).\left(1-\frac{1}{5}\right)=\frac{2}{3}.\frac{3}{4}.\frac{4}{5}=\frac{2.3.4}{3.4.5}=\frac{2}{5}.\)
b) Ta có: \(\left(1+\frac{1}{3}\right).\left(1+\frac{1}{4}\right).\left(1+\frac{1}{5}\right)=\frac{4}{3}.\frac{5}{4}.\frac{6}{5}=\frac{4.5.6}{3.4.5}=\frac{6}{3}=2\)
CHÚC BẠN HỌC TỐT
\(\left(1+\frac{1}{2}\right)\times\left(1+\frac{1}{3}\right)\times\left(1+\frac{1}{4}\right)\)
\(=\frac{3}{2}\times\frac{4}{3}\times\frac{5}{4}\)
\(=\frac{5}{2}\)
p/s: chúc bạn học tốt