2^4-50:25+37
32+5x13-13-3x2^3
2x(195+35:7):8+195
4x(3^2x(5^2+2^2):11)-26+2008
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a) 80 - [ 130 - ( 12 - 4 )2 }
= 80 - ( 130 - 82 )
= 80 - ( 130 - 64 )
= 80 - 66
= 14
b) 24 - 50 : 25 + 13 . 7
= 16 - 2 + 91
= 14 + 91
= 105
c) 2 . [ ( 195 + 35 : 7 ) : 8 + 195 ] - 400
= 2 . [ ( 195 + 5 ) : 8 + 195 ] - 400
= 2 . ( 200 : 8 + 195 ) - 400
= 2 . ( 25 + 195 ) - 400
= 2 . 220 - 400
= 440 - 400
= 40
d) 4 . { 32 [ ( 52 + 23 ) : 11 ] - 26 } + 2010
= 4 . { 9 . [ ( 25 + 8 ) : 11 ] - 26 } + 2010
= 4 . [ 9 . ( 33 : 11 ) - 26 ] + 2010
= 4 . ( 9 . 3 - 26 ) + 2010
= 4 . ( 27 - 26 ) + 2010
= 4 . 1 + 2010
= 4 + 2010
= 2014
bạn cứ tính theo thứ tự là đ,c từ từ tính ra, 0 khó đâu! mới nhìn thì thấy hơi rắc rối nhưng thiệt sự 0 khó gì đâu!
2. [(195 + 35: 7) : 8 + 195] - 400
=2.[(195 + 5) : 8 +195] - 400
=2.(200 : 8 + 195) - 400
=2.(25 + 195) - 400
=2.220-400
=440-400
=40
4.{3^2[(5^2 + 2^3) :11] -26} + 2010
=4.{3^2[(25 + 8) : 11] - 26 } +2010
=4.[3^2(33 :11)- 26] + 2010
=4.(3^2 . 3 - 26) + 2010
=4.(32+1 - 26) + 2010
=4.(3^3 - 26) + 2010
=4.(27-26) + 2010
=4.1+2010
=2014
Cách tính của minh hơi dài dòng một chút , xin lỗi bạn nha
\(\dfrac{1}{2}+\dfrac{3}{4}-\left(\dfrac{3}{4}-\dfrac{4}{5}\right)\)
=\(\dfrac{1}{2}+\dfrac{3}{4}-\dfrac{3}{4}+\dfrac{4}{5}\)
=\(\left(\dfrac{1}{2}+\dfrac{4}{5}\right)+\left(\dfrac{3}{4}-\dfrac{3}{4}\right)\)
=\(\left(\dfrac{5}{10}+\dfrac{8}{10}\right)+0\)
=\(\dfrac{13}{10}\)
\(-\dfrac{7}{25}.\dfrac{11}{13}+\left(-\dfrac{7}{25}\right).\dfrac{2}{13}-\dfrac{18}{25}\)
=\(-\dfrac{7}{25}.\cdot\left(\dfrac{11}{13}+\dfrac{2}{13}\right)-\dfrac{18}{25}\)
=\(-\dfrac{7}{25}.1-\dfrac{18}{25}\)
=\(-\dfrac{7}{25}-\dfrac{18}{25}\)
=\(-\dfrac{25}{25}\) = \(-1\)
a) \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
\(\dfrac{2}{3}x=\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{3}{5}\)
\(x=\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{9}{10}\)
b) \(\dfrac{39}{7}:x=13\)
\(x=\dfrac{\dfrac{39}{7}}{13}=\dfrac{3}{7}\)
c) \(\left(\dfrac{14}{5}x-50\right):\dfrac{2}{3}=51\)
\(\dfrac{14}{5}x-50=51\cdot\dfrac{2}{3}=34\)
\(\dfrac{14}{5}x=34+50=84\)
\(x=\dfrac{84}{\dfrac{14}{5}}=30\)
d) \(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
e) \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{5}{12}\)
\(\dfrac{1}{6}x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)
g) \(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\dfrac{11}{5}-\dfrac{3}{7}=-2\)
\(\left(x\cdot\dfrac{44}{7}+\dfrac{3}{7}\right)\cdot\dfrac{11}{5}=-2+\dfrac{3}{7}=-\dfrac{11}{7}\)
\(x\cdot\dfrac{44}{7}+\dfrac{3}{7}=-\dfrac{11}{7}:\dfrac{11}{5}=-\dfrac{5}{7}\)
\(\dfrac{44}{7}x=-\dfrac{5}{7}-\dfrac{3}{7}=-\dfrac{8}{7}\)
\(x=-\dfrac{8}{7}:\dfrac{44}{7}=-\dfrac{2}{11}\)
h) \(\dfrac{13}{4}x+\left(-\dfrac{7}{6}\right)x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x-\dfrac{5}{3}=\dfrac{5}{12}\)
\(\dfrac{25}{12}x=\dfrac{5}{12}+\dfrac{5}{3}=\dfrac{25}{12}\)
\(x=1\)
Mỏi tay woa bn làm nốt nha!!
Mình lớp 4 mà bạn
Với lại là bằng :
6''675
7785.,77
664'87'9776''8
a, 51
b, 60
c, 245