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sao 

bn ko 

tách 

ra 

từng cái 1 cho dễ

Ai bt thì làm giúp mình câu 2 và câu 3 nhé. Câu 1 mình tự làm đc r

\(v\left(t\right)=s'\left(t\right)=4\left[cos\left(2\pi t-\dfrac{\pi}{8}\right)\right]'\\ =-4\left(2\pi t-\dfrac{\pi}{8}\right)'sin\left(2\pi t-\dfrac{\pi}{8}\right)\\ =-8\pi sin\left(2\pi t-\dfrac{\pi}{8}\right)\)

Vận tốc của vật khi t = 5s là \(v\left(5\right)=-8\pi sin\left(10\pi-\dfrac{\pi}{8}\right)\approx9,6\left(m/s\right)\)

a) \(1,2^{1,5}=1,314534\)

b) \(10^{\sqrt{3}}=53,957374\)

c) \(\left(0,5\right)^{-\dfrac{2}{3}}=1,587401\)

a) \(\frac{3}{4}-\left|x\right|=\frac{2}{5}\)

\(\left|x\right|=\frac{3}{4}-\frac{2}{5}\)

\(\left|x\right|=\frac{7}{20}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{7}{20}\\x=\frac{-7}{20}\end{cases}}\)

 vậy \(\orbr{\begin{cases}x=\frac{7}{20}\\x=\frac{-7}{20}\end{cases}}\)

b) \(\frac{2}{3}:\left(2x\right)=2,7:\frac{1}{4}\)

\(\frac{2}{3}:\left(2x\right)=10,8\)

\(2x=\frac{2}{3}:10,8\)

\(2x=\frac{5}{81}\)

\(x=\frac{5}{81}:2\)

\(x=\frac{5}{162}\)

\(x\approx0,04\)

vậy  \(x\approx0,04\)

a) \(\sqrt{4\left(1+6x+9x^2\right)^2}\) = \(\sqrt{\left(2\left(1+6x+9x^2\right)\right)^2}\)

= \(\sqrt{\left(2\left(1-6\sqrt{2}+18\right)\right)^2}\) = \(2\left(1-6\sqrt{2}+18\right)\) = \(2\left(3\sqrt{2}-1\right)^2\)

= \(21,029\)

b) \(\sqrt{9a^2\left(b^2+4-4b\right)}\) = \(\sqrt{\left(3a\left(b-2\right)\right)^2}\) = \(\sqrt{\left(-6\left(-\sqrt{3}-2\right)\right)^2}\)

= \(\sqrt{\left(6\sqrt{3}+12\right)^2}\) = \(6\sqrt{3}+12\) = \(22,392\)