a: Xét ΔABE và ΔACD có

AB=AC

\(\widehat{A}\) chung

AE=AD

Do đó: ΔABE=ΔACD

\(a,\left\{{}\begin{matrix}AB=AC\\AD=AE\\\widehat{BAC}\text{ chung}\end{matrix}\right.\Rightarrow\Delta ABE=\Delta ACD\left(c.g.c\right)\\ b,\Delta ABE=\Delta ACD\\ \Rightarrow\widehat{AEB}=\widehat{ADC}\\ \Rightarrow180^0-\widehat{AEB}=180^0-\widehat{ADC}\\ \Rightarrow\widehat{BDC}=\widehat{CEB}\)

Bài 3 nhé!

Em cần bài nào em?

9: 

a: S

b: Đ

10: =-6*2/3=-4

Bài em cần đâu em?

Writing 1

1 I and my family have just returned from a trip to Da Lat

2 It was about 30 kilometers from my house, so we went there by bus

3 Da Lat was beautiful and clean

4 The people were friendly and the weather was cool and cloudy

5 We felt happy and excited after the trip

Writing 2

1 Thank you so much for the flowers you sent me last week

2 They were beautiful and they really help cheering me up

3 I came out of the hospital on Monday morning

4 Now I am sad. Will you come to my place next weekend?

a. \(4\dfrac{1}{4}-2\dfrac{5}{8}+2\dfrac{3}{5}=\dfrac{17}{4}-\dfrac{21}{8}+\dfrac{13}{5}=\dfrac{169}{40}\)

b. \(4\dfrac{4}{9}:2\dfrac{2}{3}+3\dfrac{1}{6}=\dfrac{40}{9}:\dfrac{8}{3}+\dfrac{19}{6}=\dfrac{5}{3}+\dfrac{19}{6}=\dfrac{29}{6}\)

c. \(3\dfrac{1}{5}+2\dfrac{3}{5}-2\dfrac{4}{5}=\dfrac{16}{5}+\dfrac{13}{5}-\dfrac{14}{5}=\dfrac{16+13-14}{5}=\dfrac{15}{5}=3\)

d. \(5\dfrac{1}{7}-2\dfrac{4}{5}:1\dfrac{1}{5}=\dfrac{36}{7}-\dfrac{14}{5}:\dfrac{6}{5}=\dfrac{36}{7}-\dfrac{7}{3}=\dfrac{59}{21}\)

e. \(2\dfrac{3}{5}+1\dfrac{1}{4}.2\dfrac{2}{3}=\dfrac{13}{5}+\dfrac{5}{4}.\dfrac{8}{3}=\dfrac{13}{5}+\dfrac{10}{3}=\dfrac{89}{15}\)

g. \(4\dfrac{1}{3}.1\dfrac{1}{2}+5\dfrac{2}{7}=\dfrac{13}{3}.\dfrac{3}{2}+\dfrac{37}{7}=\dfrac{13}{2}+\dfrac{37}{7}=\dfrac{165}{14}\)

Bài 1:

\(a.8,6\\ b.54,76\\ c.43,562\\ d.13,035\\ e.0,101\\ g.55,555\)

giải cả bài 2 cho mình với ạ