\(\frac{13}{15}< \frac{11}{13}\)

\(\frac{8}{5}< \frac{7}{4}\)

\(\frac{8}{9}< \frac{4}{5}\)

\(\frac{7}{15}< \frac{21}{4}\)

Theo thứ tự≥≥≥= k mik nhé!

a/\(\frac{1212}{1313}=\frac{12x101}{13x101}=\frac{12}{13}\)

Vậy \(\frac{12}{13}=\frac{1212}{1313}\)

b/Ta có:

\(\frac{4}{5}< 1\)

\(\frac{10}{9}>1\)

=>\(\frac{4}{5}< 1< \frac{10}{9}\Rightarrow\frac{4}{5}< \frac{10}{9}\)

c/\(\frac{17}{15}=1+\frac{2}{15}\)

\(\frac{31}{29}=1+\frac{2}{29}\)

Vì \(\frac{2}{15}>\frac{2}{29}\) nên \(\frac{17}{15}>\frac{31}{29}\)

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chú ý: dấu "=>" có nghĩa là "suy ra"

D(=)

E(<)

F(>)

Tham Khảo:

a: 0. ( 4 ) = \(\dfrac{4}{9}\) = \(\dfrac{16}{36}\)<\(\dfrac{27}{36}\)=\(\dfrac{3}{4}\)

d: -0,2<-0,1(9)

a, 3/4 > 0,(4)

b, 3,21(13) > 3,(2)

c, 2,3(496) < 47/20

d, -0,2 < -0,1(9)

giúp minh với mình cần gấp á

a: \(0.\left(4\right)=\dfrac{4}{9}=\dfrac{16}{36}< \dfrac{27}{36}=\dfrac{3}{4}\)

d: -0,2<-0,1(9)

a)\(10^{20}=\left(10^2\right)^{10}=100^{10}\left(1\right)\)

\(9^{30}=\left(9^3\right)^{10}=729^{10}\left(2\right)\)

Từ (1) và (2) \(\Rightarrow9^{30}>10^{20}\)

b) \(\left(-5\right)^{30}=5^{30}=125^{10}\)

\(\left(-3\right)^{50}=3^{50}=243^{10}\)

\(\Rightarrow\left(-3\right)^{50}>\left(-5\right)^{30}\)

c)\(64^8=\left(2^6\right)^8=2^{48}\)

\(16^{12}=\left(2^4\right)^{12}=2^{48}\)

\(\Rightarrow64^8=16^{12}\)

Xét: 8.(9+m)=72+8m

9.(8+m)=72+9m

Với m E N* thì 8m<9m

=>72+8m<72+9m

=>8.(9+m)<9.(8+m)

=>8/9<8+m/9+m

Ta thấy: \(\frac{8}{9}=\frac{8.\left(9+m\right)}{9.\left(9+m\right)}=\frac{72+8m}{81+9m}\)

\(\frac{8+m}{9+m}=\frac{9.\left(8+m\right)}{9.\left(9+m\right)}=\frac{72+9m}{81+9m}\)

Vì 72+8m<72+9m (m thuộc N*) nên: \(\frac{72+8m}{81+9m}<\frac{72+9m}{81+9m}\)

hay \(\frac{8}{9}<\frac{8+m}{9+m}\)

sao chưa ai gửi trả lời cho mình vây huhu

help me ai nhanh mình tích

9¹² = (3²)¹² = 3²⁴

27⁷ = (3³)⁷ = 3²¹

Vì 3²⁴ > 3²¹

=> 9¹² > 27⁷

Bạn ghi rõ cách làm ra giúp mình!

Ta có : \(\left(-32\right)^9=-32^9\)

\(\left(-18\right)^{13}=-18^{13}\)

Ta có : \(-32^9=-\left(2^5\right)^9=-2^{45}>-2^{52}=-\left(2^4\right)^{13}=-16^{13}>-18^{13}\)

Mà \(32^{27}< 18^{39}\)

Nên \(\left(-32\right)^9>\left(-18\right)^{19}\)  ( đpcm )