Tìm N,x biết:
[(123x-456)]+25=1256
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e xin tra loi phep tinh nay 123*456+567=56655
tic cho e nha
Bài 6:
\(21,251+6,058+0,749+1,042\)
\(=\left(21,251+0,749\right)+\left(6,058+1,042\right)\)
\(=22+7,1\)
\(=29,1\)
___________________
\(1,53+5,309+12,47+5,691\)
\(=\left(1,53+12,47\right)+\left(5,309+5,691\right)\)
\(=14+11\)
\(=25\)
5:
a: =>x/17=5/17
=>x=5
b; =>6+x=7/11*33=21
=>x=15
c: \(\dfrac{12+x}{43-x}=\dfrac{2}{3}\)
=>3x+36=86-2x
=>5x=50
=>x=10
d: \(\dfrac{x}{5}< \dfrac{3}{7}\)
=>x<3/7*5
=>x<15/7
f: 15/26+x/16=46/52
=>x/16=23/26-15/26=8/26=4/13
=>x=4/13*16=64/13
thay x = 122 vào biểu thức A(x) = x4 - 123x3 + 123x2 - 123x + 125 ta có :
A(x) = 1224 - 123.1223 + 123.1222 - 123.122 + 125
= 221533456 - 223349304 + 1830732 - 15006 + 125
= 3
a) \(???\)
b) \(123x+877x=2000\)
\(1000x=2000\)
\(x=2000:1000\)
\(x=2\)
c) \(2x.\left(x-10\right)=0\)
=> \(x-10=0\)
\(x=10\)
d)\(6.\left(x+2\right)-\left(4x+10\right)=100\)
\(6.x+12-4x+10=100\)
\(2x+2=100\)
\(2x=98\)
\(x=98:2\)
\(x=49\)
e) \(x.\left(x+1\right)=2+4+6+8+...+2500\)
\(x.\left(x+1\right)=1563750\)
mà ta thấy : \(1250.1251=1563750\)
=> \(x=1250\)
g)\(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5750\)
\(x.100+5050=5750\)
\(x.100=5750-5050\)
\(x.100=700\)
\(x=7\)
a) x - 1234 = 4567
x = 4567+1234
x = 5801
b) x + 453 = 4541
x = 4541 - 453
x = 4088
c) x : 1256 = 12
x = 12 x 1256
x = 15 072
1001x112x123x=1001x123.x123
=> 112x=123 => x=123/112
[(123x-456)]+25=1256
=>123x-456=1231
=>123x=1687
=>x=1687/123
\(\left[\left(123x-456\right)\right]+25=1256\)
\(123x-456=1231\)
\(123x=1231+456\)
\(123x=1687\)
\(x=1687:123\)
\(x=13\frac{88}{123}\)
Vậy \(x=13\frac{88}{123}\)