Tìm x:
X - 0,25 = 43/4 + 18/5
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x+0,25=3,6+10,75
x+0,25=14,35
x+0,25=14,35-0,25
x+0,25=14,1
x =14,1-0,25
x=13,85
ta có
x + 0,25 = 43/4 - 18/5
=> x + 1/4 = 143/20
=> x = 143/20 - 1/4
=> x = 25/4
vậy x = 25/4
`x+0,25=18/5+43/4`
`x+0,25=3,6+10,75`
`x=3,6+10,5`
`x=14,1`
Vậy `x=14,1`
`x+0,25=18/5+43/4`
`⇔x+1/4=18/5+43/4`
`⇔ x-18/5=43/4-1/4`
`⇔ x-18/5=42/4=21/2`
`⇔ x-36/10=105/10`
`⇔ x=141/10`
x+0,25 =\(\frac{18}{5}+\frac{43}{4}\)
\(x+\frac{1}{4}-\frac{18}{5}-\frac{43}{4}=0\)
\(\frac{20x+5-72-215}{20}=0\)
20x-282 =0
x= \(\frac{282}{20}\)
x= \(\frac{141}{10}\)
Vậy x=141/10
a.
\(1,25\times4-x=2,5\)
\(5-x=2,5\)
\(x=5-2,5\)
\(x=2,5\)
b.
\(\left(158-x\right)\div7=20\)
\(158-x=20\times7\)
\(158-x=140\)
\(x=158-140\)
\(x=18\)
c.
\(x-0,25=\frac{43}{4}-\frac{18}{5}\)
\(x-\frac{1}{4}=\frac{43}{4}-\frac{18}{5}\)
\(x=\frac{43}{4}-\frac{18}{5}+\frac{1}{4}\)
\(x=\left(\frac{43}{4}+\frac{1}{4}\right)-\frac{18}{5}\)
\(x=\frac{44}{4}-\frac{18}{5}\)
\(x=11-\frac{18}{5}\)
\(x=\frac{37}{5}\)
a. 1,25 × 4 - x = 2,5
5- x= 2,5
x= 5-2,5
x=2,5
b.(158- x) :7= 20
158- x= 20x7
158 -x= 140
x=158- 140
x=18
c. x- 0,25= \(\frac{43}{4}+\frac{18}{5}\)
x- 0,25=14,35
x= 14,35+ 0,25
x=14,6
\(x\) + \(x\): 0,25 + \(x\) : 0,5 + \(x\) : 0,125 = 40
\(x\) \(\times\) 1+ \(x\) \(\times\) 4 + \(x\) \(\times\) 2 + \(x\times\) 8 = 40
\(x\) \(\times\) ( 1 + 4 + 2 + 8) = 40
\(x\) \(\times\) 15 = 40
\(x\) = 40 : 15
\(x\) = \(\dfrac{8}{3}\)
x - 0,25 = 43/4 + 18/5
\(x-\frac{1}{4}=\frac{287}{20}\)
\(x=\frac{287}{20}+\frac{1}{4}\)
\(x=\frac{73}{5}\)
\(x-0,25=\frac{43}{4}+\frac{18}{5}\)
\(\Rightarrow x-\frac{1}{4}=\frac{43}{4}+\frac{18}{5}\)
\(\Rightarrow x-\frac{1}{4}=\frac{287}{20}\)
\(\Rightarrow x=\frac{287}{20}+\frac{1}{4}\)
\(\Rightarrow x=\frac{73}{5}\)
\(\Rightarrow x=14,6\)