a) \(4x^2\left(5x-3y\right)-x^2\left(4x+y\right)=20x^3-12x^2y-4x^3-x^2y=16x^3-13x^2y\)

b) \(2ax^2-a\left(1+2x^2\right)-\left[a-x\left(x+a\right)\right]\)

\(=2ax^2-a-2ax^2-a+x^2+ax=x^2+ax-a\)

ol mà ko thèm nt vs a nha !!!!!

\(\dfrac{2a\cdot x^2-4ax+2a}{5b-5bx^2}\)

\(=\dfrac{2a\left(x^2-2x+1\right)}{5b\left(1-x^2\right)}\)

\(=\dfrac{-2a\left(x-1\right)^2}{5b\left(x-1\right)\left(x+1\right)}=\dfrac{-2a\left(x-1\right)}{5b\left(x+1\right)}\)

\(\dfrac{4x^2-4xy}{5x^3-5x^2y}\)

\(=\dfrac{4x\cdot x-4x\cdot y}{5x^2\cdot x-5x^2\cdot y}\)

\(=\dfrac{4x\left(x-y\right)}{5x^2\left(x-y\right)}=\dfrac{4}{5x}\)

\(\dfrac{\left(x+y\right)^2-z^2}{x+y+z}\)

\(=\dfrac{\left(x+y+z\right)\left(x+y-z\right)}{x+y+z}\)

=x+y-z

\(\dfrac{x^6+2x^3y^3+y^6}{x^7-xy^6}\)

\(=\dfrac{\left(x^3+y^3\right)^2}{x\left(x^6-y^6\right)}\)

\(=\dfrac{\left(x^3+y^3\right)^2}{x\left(x^3+y^3\right)\left(x^3-y^3\right)}=\dfrac{x^3+y^3}{x\left(x^3-y^3\right)}\)

a) \(\frac{x^2-y^2}{\left(x+y\right)\left(ay-\text{ax}\right)}=\frac{\left(x+y\right)\left(x-y\right)}{-a\left(x+y\right)\left(x-y\right)}=\frac{-1}{a}\)

b) \(\frac{2ax-2x-3y+3ay}{4ax+\text{4x}+6y+6ay}=\frac{2x\left(a-1\right)+3y\left(a-1\right)}{\text{4x}\left(a+1\right)+6y\left(a+1\right)}\)

\(=\frac{\left(a-1\right)\left(2x+3y\right)}{2\left(a+1\right)\left(2x+3y\right)}=\frac{a-1}{2\left(a+1\right)}\)

lêu lêu lêu 

Bài 1:

a, 2x(x - 3y )

= 2x² - 6y

b, ( x - 2y ) ( x² - 2xy + y² )

= x³ - 2x²y + xy² - 2x²y + 4xy² - 2y³

= x³ -4 x²y + 5xy³ - 2y³

Bài 2: 

5x( 4x² - 2x + 1 ) - 2x ( 10x² - 5x - 2 )

= 20x³ - 10x² + 5x - 20x³ + 10x² + 4x

= 9x

( don't k ❤EXO❤ )

a)=(x^2-x-6)-(x^2-x-5)

=x^2-x-6-x^2+x+5

=-1

b)đề bài kì cục

Không ai trả lời luôn

\(a,4x^2\left(5x-3y\right)-5x^2\left(4x+y\right)\)

\(=20x^3-12x^2y-20x^3-5x^2y\)

\(=-17x^2y=-17\left(-2\right)^2.\left(-3\right)=204\)

\(b,\left(x-4\right)\left(x-2\right)-\left(x-1\right)\left(x-3\right)\)

\(=x^2-6x+8-x^2+4x-3\)

\(=-2x+5=-2.74+5=143\)