Tính: \(=\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}=\frac{11.3^{29}-3^{30}}{4.3^{28}}=\frac{3^{28}\left(11.3-3^2\right)}{4.3^{28}}=\frac{24}{4}=6\)

Tìm x:

<=> (2x-15)⁷- (2x-15)⁵=0

<=>  (2x-15)⁵  .[(2x-15)²-1]=0

<=>  (2x-15)⁵ = 0  hoặc (2x-15)²-1 = 0

+) (2x-15)⁵=0 <=> 2x - 15 = 0 <=> x = 15/2

+) (2x-15)² - 1 = 0 <=>  (2x-15)² = 1 <=> 2x - 15 = 1 <=> 2x = 16 <=> x = 8 hoặc 2x - 15 = -1 <=> 2x = 14 <=> x = 7

Vậy x = {15/2 ;  8 ; 7}

tìm chứ số tận cùng

58³³= 58.58³² = 58. (58²)¹⁶ = 58. (....4)¹⁶ = 58. (....4²)⁸ = 58. (....6)⁸  = 58 x ....6 =....8

a) 2^x-15= 17

    2^x      = 17-15

   2^x        =  2

   2^x         =  2¹

  x             =   1                      

\(\frac{11.3^{22}.3^7-9^{15}}{\left(3^{14}\right)^2}\)

\(=\frac{11.3^{29}-3^{30}}{3^{28}}\)

\(=\frac{3^{29}.\left(11-3\right)}{3^{28}}\)

\(=3.8=24\)

\(\frac{11.3^{22}.3^7-9^{15}}{ \left(3^{14}\right)^2}\)

= \(\frac{11.3.3^{21}.3^7-\left(3^2\right)^{15}}{\left(3^{14}\right)^2}\)

= \(\frac{33.3^{28}-3^{30}}{3^{28}}\)

= \(\frac{33.3^{28}-3^{28}.9}{3^{28}}\)

= \(\frac{3^{28}.\left(33-9\right)}{3^{28}}\)

= \(\frac{24}{1}=24\)

a) 2^x - 15 = 17

2^x = 2⁵

b) ( 7x - 11 )³ = 2⁵. 5² + 200

(7x - 11)³ = 32 . 25 + 200

(7x -11)³ = 1000

(7x-11)³ = 10³

7x - 11 = 10

7x = 10+11

7x = 21

x = 21 : 7

x = 3

like nha

A=\(\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\dfrac{11.3^{29}-3^{29}.3}{2^2.3^{28}}=\dfrac{3^{29}.\left(11-3\right)}{2^2.3^{28}}=\dfrac{3^{29}.2^3}{2^2.3^{28}}=3.2=6\)

là ơn giúp với 

help me 

help me !

6

mình cần diễn giải hen

ta có    \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}\)

=  \(\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}\left(11-3\right)}{2^2.3^{28}}\)

=   \(\frac{3^{29}.2^3}{2^2.3^{28}}=3.2=6\)