\(N=\dfrac{2^6\cdot3^6+2^3\cdot3^3\cdot3^3+3^6}{-73}=\dfrac{3^6\left(2^6+2^3+1\right)}{-73}=\dfrac{3^6\cdot73}{-73}=-3^6=-729\)

\(B=\dfrac{6^6+6^3.3^3+3^6}{-73}\)

\(B=\dfrac{46656+5832+729}{-73}\)

\(B=\dfrac{52488+729}{-73}\)

\(B=\dfrac{53217}{-73}=-729\)

\(\dfrac{6^6+6^3\cdot3^3+3^6}{-7^3}\)

\(=\dfrac{46656+46656\cdot27+729}{-343}\)

\(=\dfrac{46656+1259712+729}{-343}\)

\(=\dfrac{1306368+729}{-343}\)

\(=\dfrac{1307097}{-343}\)

\(\dfrac{6^6+6^3.3^3+3^6}{-73}=\dfrac{3^6.2^6+3^3.2^3.3^3+3^6}{-73}=\dfrac{3^6.64+3^6.8+3^6}{-73}=\dfrac{3^6.\left(64+8+1\right)}{-73}=-3^6=-729\)

Giải:

\(\dfrac{6^6+6^3.3^3+3^6}{-73}=\dfrac{2^6.3^6+2^3.3^3.3^3+3^6}{-73}\)

\(=\dfrac{2^6.3^6+2^3.3^6+3^6}{-73}=\dfrac{3^6\left(2^6+2^3+1\right)}{-73}\)

\(=\dfrac{3^6\left(64+8+1\right)}{-73}=\dfrac{3^6.73}{-73}=-3^6=-729.\)

Vậy.....

\(\dfrac{6^6+6^3.3^3+3^6}{-73}\)

\(\dfrac{3^6.2^6+3^6.2^3+3^6.1}{-73}\)

\(\dfrac{3^6.\left(2^6+2^3+1\right)}{-73}\)

\(=\dfrac{3^6.73}{-73}=-729\)

\(\dfrac{6^6+6^3.3+6^3}{-73}=\dfrac{2^6.3^6+2^3.3^3.3+2^6.3^6}{-73}=\dfrac{2^6.3^6+2^3.3^4+2^6.3^6}{-73}=\dfrac{2^3.3^4.\left(2^{3^{ }}.3^2+1+2^{3^{ }}.3^{2^{ }}\right)}{-73}=\dfrac{93960}{-73}\)

Vương Hạ Di chép sai đề => kq sai :w

\(=\dfrac{3^6\cdot2^6+3^3\cdot3^3\cdot2^3+3^6}{-73}=\dfrac{3^6\left(2^6+2^3+1\right)}{-73}=-3^6=-729\)

\(\dfrac{6^6+6^3.3^3+3^6}{-73}=\dfrac{46656+\left(6.3\right)^3+729}{-73}=\dfrac{46656+18^3+729}{-73}=\dfrac{46656+5832+729}{-73}=\dfrac{53217}{-73}=-729\)

\(\frac{6^6+6^3.3^3+3^6}{-73}\)

\(=\frac{3^6.\left(2^6+2^3+1\right)}{-73}\)

\(=\frac{3^6.73}{-73}\)

\(=3^6.\left(-1\right)=-729\)