a) \(\left(4x-1\right)^2=9\)

\(\left(4x-1\right)^2=3^2\)

\(\Rightarrow4x-1=3\)

\(\Rightarrow4x=4\)

\(\Rightarrow x=1\)

vay \(x=1\)

b) \(3^{2x-3}=9\)

\(3^{2x-3}=3^2\)

\(\Rightarrow2x-3=2\)

\(\Rightarrow2x=5\)

\(\Rightarrow x=\frac{5}{2}\)

vay \(x=\frac{5}{2}\)

a. (4xX-1)^2 = 9

(4xX-1)^2 = 3^2

4xX-1 = 3

4xX =3+1

4xX = 4

X =4:4

X = 1

\(75\%x+\frac{3}{4}x+x=30\)

\(\Leftrightarrow\left(75\%+\frac{3}{4}+1\right)x=30\)

\(\Leftrightarrow\frac{5}{2}x=30\)

\(\Leftrightarrow x=30:\frac{5}{2}\)

\(\Leftrightarrow x=12\)

đổi 75%=3/4.Ta có:

3/4xX+3/4xX+X=30

(3/4+3/4+1)xX=30

    5/2     x    X=30

                 X  = 30:5/2

                X   = 12

\(75\%\times x+\frac{3}{4}\times x+x=30\)

\(\frac{3}{4}\times x+\frac{3}{4}\times x+1\times x=30\)

\(\left(\frac{3}{4}+\frac{3}{4}+1\right)\times x=30\)

\(\frac{5}{2}\times x=30\)

\(x=30\div\frac{5}{2}\)

\(x=12\)

0,75 x X + 0,75 x X + X = 30

X x ( 0,75 + 0,75 + 1 ) = 30

X x 2,5 = 30

X = 30 : 2,5

X = 12

75%xX+3/4xX+X=30

<=>3/4xX+3/4xX+X=30

<=>10/4xX=30

<=>10xX=120

<=>X=120/10=12

Vậy X=12

0,75x + 0,75x = 30

0,75 . 2x = 30

2x = 40

x = 20

\(75\%\cdot x+\frac{3}{4}\cdot x+x=30\)

\(x\cdot\left(\frac{3}{4}+\frac{3}{4}+1\right)=30\)

\(x\cdot\frac{5}{2}=30\)

\(x=30\cdot\frac{2}{5}\)

\(x=12\)

xX là biến hả 

phải tìm x rồi giải nha bạN

\(\frac{3}{8}\times x+\frac{1}{4}\times x=\frac{2}{5}\)

\(\Rightarrow x\times\left(\frac{3}{8}+\frac{1}{4}\right)=\frac{2}{5}\)

\(\Rightarrow x\times\frac{5}{8}=\frac{2}{5}\)

\(\Rightarrow x=\frac{16}{25}\)

~Std well~

#Thạc_Trân

bn ơi / là j bn

cậu có viết thừa ko vậy

4x+3 chia hết cho x-2

=> 4x-8+11 chia hết cho x-2

=> 4(x-2)+11 chia hết cho x-2

=> 4(x-2) chia hết cho x-2 ; 11 chia hết cho x-2

=> x-2 thuộc Ư(11)={-1,-11,1,11}

Ta có bảng :

Vậy x={-9,1,3,13}

a) \(\dfrac{13}{6}\)b) \(\dfrac{7}{18}\)c) \(5\) d) \(\dfrac{2}{3}\)

1.

a)x\(=\)\(\dfrac{7}{6}\)\(-\dfrac{2}{3}\)

  x\(=\dfrac{1}{2}\)

b)x\(=\dfrac{9}{2}:\dfrac{3}{4}\)

   x\(=6\)

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