tim x biet : 720 : [ 41- ( 2 * x - 5 ) ] = 8 * 4
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Tìm x thuoc z:
1) \(26-\left|x+9\right|=-13\)
\(\Leftrightarrow\left|x+9\right|=26-\left(-13\right)\)
\(\Leftrightarrow\left|x+9\right|=39\)
\(\Leftrightarrow\left[{}\begin{matrix}x+9=39\\x+9=-39\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=39-9=30\\x=-39-9=-48\end{matrix}\right.\)
Vậy: \(x\in\left\{30;-48\right\}\)
2) \(\left|x+7\right|-13=25\)
\(\Leftrightarrow\left|x+7\right|=25+13=38\)
\(\Leftrightarrow x+7\in\left\{38;-38\right\}\)
\(\Leftrightarrow x\in\left\{31;-45\right\}\)
Vậy:.................
tim x biet
\(1)123-3.\left(x+4\right)=23\)
\(\Leftrightarrow3\left(x+4\right)=123-23\)
\(\Leftrightarrow3\left(x+4\right)=100\)
\(\Leftrightarrow x+4=\frac{100}{3}\)
\(\Leftrightarrow x=\frac{100}{3}-4=\frac{100-12}{3}=\frac{88}{3}\)
Vậy:................
2) Tương tự
a)13/17 < 15/19
a) 2/3 x X + 3/4 = 3
2/3 x X = 3 - 3/4
2/3 x X = 9/4
X = 9/4 : 2/3
X = 27/8
a. Ta có : \(\frac{13}{17}=\frac{247}{323};\frac{15}{19}=\frac{255}{323}\)
Vì 255 > 247 nên 247/323 < 255/323
Hay \(\frac{13}{17}< \frac{15}{19}\)
b. \(\frac{2}{3}\times x+\frac{3}{4}=3\)
\(\frac{2}{3}\times x=3-\frac{3}{4}\)
\(\frac{2}{3}\times x=\frac{9}{4}\)
\(x=\frac{9}{4}:\frac{2}{3}\)
\(x=\frac{27}{8}\)
c. \(720:\left[41-\left(2\times x-5\right)\right]=120\)
\(\left[41-\left(2\times x-5\right)\right]=720:120\)
\(41-\left(2\times x-5\right)=6\)
\(2\times x-5=35\)
\(2\times x=40\)
\(x=20\)
a) \(\left[\left(4x+28\right).3+55\right]:5=35\)
\(\Leftrightarrow\left(4x+28\right).3+55=35.5\)
\(\Leftrightarrow\left(4x+28\right).3+55=175\)
\(\Leftrightarrow\left(4x+28\right).3=175-55\)
\(\Leftrightarrow\left(4x+28\right).3=120\)
\(\Leftrightarrow4x+28=120:3\)
\(\Leftrightarrow4x+28=40\)
\(\Leftrightarrow4x=40-28\)
\(\Leftrightarrow4x=12\)
\(\Leftrightarrow x=12:4\)
\(\Leftrightarrow x=3\)
Vậy \(x=3\)
b) \(\left(12x-4^3\right).8^3=4.8^4\)
\(\Leftrightarrow12x-4^3=4.8^4:8^3\)
\(\Leftrightarrow12x-4^3=4.8^{4-3}\)
\(\Leftrightarrow12x-4^3=4.8\)
\(\Leftrightarrow12x-4^3=32\)
\(\Leftrightarrow12x-64=32\)
\(\Leftrightarrow12x=32+64\)
\(\Leftrightarrow12x=96\)
\(\Leftrightarrow x=96:12\)
\(\Leftrightarrow x=8\)
Vậy \(x=8\)
c) \(720:\left[41-\left(2x-5\right)\right]=2^3.5\)
\(\Leftrightarrow720:\left[41-\left(2x-5\right)\right]=8.5\)
\(\Leftrightarrow720:\left[41-\left(2x-5\right)\right]=40\)
\(\Leftrightarrow41-\left(2x-5\right)=720:40\)
\(\Leftrightarrow41-\left(2x-5\right)=18\)
\(\Leftrightarrow2x-5=41-18\)
\(\Leftrightarrow2x-5=23\)
\(\Leftrightarrow2x=23+5\)
\(\Leftrightarrow2x=28\)
\(\Leftrightarrow x=28:2\)
\(\Leftrightarrow x=14\)
Vậy \(x=14\)
720 : [ 41 - ( 2 x x -5 ) =120
41 - ( 2 x x - 5 ) = 720 : 120
41 - ( 2 x \(x\) -5 ) =6
2 x \(x\) -5 = 41 - 6
2 x \(x\) - 5 = 35
2 x \(x\) = 35+5
2 x \(x\)=40
\(x\) = 40 : 2 = 20
Vậy x = 20
Ủng hộ nhé ^^
720 : [ 41 - ( 2 x X - 5 ) ] = 120
41 - ( 2 x X - 5 ) = 720 : 120
41 - ( 2 x X - 5 ) = 6
2 x X - 5 = 41 - 6
2 x X - 5 = 35
2 x X = 35 - 5
2 x X = 30
X = 30 : 2
X = 15
Học tốt nhé bạn !
720 : [ 41 - ( 2x-5)] = 2^3 .5
=> 720 :[ 41- (2x-5)] = 40
=> 41 - (2x-5) = 18
=> 2x -5 = 23
=> 2x = 28
=> x=14
255 - 21 . 5 . ( 198 : 11 - 8 )
= 255 - 105 . ( 18 - 8 )
= 255 - 105 . 10
= 255 - 1050
= -795
720 : [ 41 - ( 2 . x . 5 ) ] = 23 . 5
720 : [ 41 - ( 10 . x ) ] = 40
41 - ( 10 . x ) = 720 : 40
41 - ( 10 . x ) = 18
10 . x = 41 - 18
10 . x = 23
x = 23/10
\(720:\left[41-\left(2\times x+5\right)\right]=8\times4\)
\(720:\left[41-\left(2\times x+5\right)\right]=32\)
\(41-\left(2\times x+5\right)=720:32\)
\(41-\left(2\times x+5\right)=22,5\)
\(2\times x+5=41-22,5\)
\(2\times x+5=18,5\)
\(2\times x=18,5-5\)
\(2\times x=13,5\)
\(x=13,5:2\)
\(x=6,75\)
11,75 . TOK chúc BẠN học tốt !