Tính bằng các thuận tiện: 10/7 x 2/3 + 5/6 : 3/10 - 2/3 x 3/7
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\(\frac{1}{7}\cdot\frac{2}{3}+\frac{5}{6}:\frac{3}{10}-\frac{2}{3}\cdot\frac{3}{7}\)
\(=\left(\frac{1}{7}\cdot\frac{2}{3}-\frac{2}{3}\cdot\frac{3}{7}\right)+\frac{5}{6}\cdot\frac{10}{3}\)
\(=\frac{2}{3}\cdot\left(-\frac{2}{7}\right)+\frac{5}{3}\cdot\frac{5}{3}\)
\(=-\frac{4}{21}+\frac{25}{6}=\frac{167}{42}\)
Xin lỗi không nhanh được
Tính bằng các thuận tiện nhất: 10/7 x 2/3 + 6/5 : 3/10 - 2/3 x 3/7
trả lời:
10/7 x 2/3 + 6/5 : 3/10 - 2/3 x 3/7=10/7 x 2/3 + 6/5. 10/3 - 2/3 x 3/7=10/7 x 2/3 + 2/3.2- 2/3 x 3/7
=2/3.(10/7+2-3/7)=2/3.3=2
10/7 x 2/3 + 6/5 : 3/10 - 2/3 x 3/7
= 10/7 x 2/3 + 6/5 x 10/3 - 2/3 x 3/7
= 10/7 x 2/3 + 6/5 x 5 x 2/3 - 2/3 x 3/7
= 10/7 x 2/3 + 6 x 2/3 - 2/3 x 3/7
= 2/3 x (6 + 10/7 - 3/7)
= 2/3 x (6 + 1)
= 2/3 x 7
= 14/3
CHúc bạn học tốt
3.12:0.25+12.48*3-3.12*6
=3.12*4+3.12*12-3.12*6
=3.12*(4+12-6)
=3.12*10
=31.2
3,12 : 0,25 + 12,48 x 3 - 3,12 x 6
= 3,12 x 4 + 3,12 x ( 4 x 3 ) - 3,12 x 6
= 3,12 x 4 + 3,12 x 12 - 3,12 x 6
= 3,12 x ( 4 + 12 - 6 )
= 3,12 x 10
= 31,2
3,12 : 0,25 + 12,48 x 3 - 3,12 x 6
=3,12 : 1/4 + 3,12 x 4 x 3 - 3,12 x 6
=3,12 x 4 + 3,12 x 12 - 3,12 x 6
=3,12 x (4 + 12 - 6)
=3,12 x 10
=31,2
Bài 1:
1+2+3+4+5+5+6+7+8+9
=(1+9)+(2+8)+(3+7)+(4+6)+(5+5)
=10+10+10+10+10
=50
Bài 2:
3*2*2*2*10*10*10*10
=3*(2*3)*(10*4)
=3*6*40
=640
hok tốt (đúng chưa vậy)
\(10.4^6.9^5+6^9.120:8^4.3^{12}-6^{11}\)
\(=2.5.2^{12}.3^{10}+3^9.2^9.2^3.3.5:2^{12}.3^{12}-3^{11}.2^{11}\)
\(=5.2^{13}.3^{10}+2^{12}.5:2^{12}.3^{22}-3^{11}.2^{11}\)
\(=5.2^{13}.3^{10}+5.3^{22}-3^{11}.2^{11}\)
\(=5.3^{10}.\left(2^{13}+3^{12}\right)-3^{11}.2^{11}\)
3 x 7/10 + 7/10 x 5 + 2 x 7/10
= 7/10 x (3 + 5 + 2)
= 7/10 x 10
= 7
\(\dfrac{7}{10}\times\left(3+5+2\right)=\dfrac{7}{10}\times10=\dfrac{70}{10}=7\)
\(\frac{10}{7}\cdot\frac{2}{3}+\frac{5}{6}:\frac{3}{10}-\frac{2}{3}\cdot\frac{3}{7}\)
\(=\left(\frac{10}{7}\cdot\frac{2}{3}-\frac{2}{3}\cdot\frac{3}{7}\right)+\frac{5}{6}\cdot\frac{10}{3}\)
\(=\frac{2}{3}\left(\frac{10}{7}-\frac{3}{7}\right)+\frac{5\cdot10}{6\cdot3}\)
\(=\frac{2}{3}\cdot1+\frac{25}{9}\)
\(=\frac{2}{3}+\frac{25}{9}\)
\(=\frac{31}{9}\)