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x^2 + x - 12 phân tích đa thức này ra nhân tử bằng kỹ thuật bổ sung hằng đẳng thức giùm em đi ạ :))) em camon nhiều :>
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c ) \(x^2-7x+12\)
\(=\left(x^2-3x\right)-\left(4x-12\right)\)
\(=x\left(x-3\right)-4\left(x-3\right)\)
\(=\left(x-4\right)\left(x-3\right)\)
d ) \(x^2+7x+12\)
\(=\left(x^2+3x\right)+\left(4x+12\right)\)
\(=x\left(x+3\right)+4\left(x+3\right)\)
\(=\left(x+4\right)\left(x+3\right)\)
x2 + x -12 = x2 + 4x - 3x - 12 = x(x+4) - 3(x+4) = (x+4)(x-3)
\(x^2+x-12\)
\(=x^2+x+\frac{1}{4}-\frac{49}{4}\)
\(=\left(x+\frac{1}{2}\right)^2-\left(\frac{7}{2}\right)^2\)
\(=\left(x+\frac{1}{2}-\frac{7}{2}\right)\left(x+\frac{1}{2}+\frac{7}{2}\right)\)
\(=\left(x-3\right)\left(x+4\right)\)
a ) \(x^2-5x+6\)
\(=\left(x^2-2x\right)-\left(3x-6\right)\)
\(=x\left(x-2\right)-3\left(x-2\right)\)
\(=\left(x-2\right)\left(x-3\right)\)
b )\(x^2+5x+6\)
\(=\left(x^2+2x\right)+\left(3x+6\right)\)
\(=x\left(x+2\right)+3\left(x+2\right)\)
\(=\left(x+2\right)\left(x+3\right)\)
a.x^2 - 5x + 6
=x2-2x-3x+6
=x(x-2)-3(x-2)
=(x-3)(x-2)
b.x^2 + 5x + 6
=x2+3x+2x+6
=x(x+3)+2(x+3)
=(x+2)(x+3)
a: =4x^2+8x-3x-6
=4x(x+2)-3(x+2)
=(x+2)(4x-3)
b: =3(3x^2-2x-1)
=3(3x^2-3x+x-1)
=3(x-1)(3x+1)
c: =2x^2-4x+x-2
=2x(x-2)+(x-2)
=(x-2)(2x+1)
d: =3x^2+3x-2x-2
=3x(x+1)-2(x+1)
=(x+1)(3x-2)
e: =3x^2+9x+x+3
=3x(x+3)+(x+3)
=(x+3)(3x+1)
a) \(4x^2+5x-6\)
\(=4x^2+8x-3x-6\)
\(=\left(4x^2+8x\right)-\left(3x+6\right)\)
\(=4x\left(x+2\right)-3\left(x+2\right)\)
\(=\left(x+2\right)\left(4x-3\right)\)
b) \(9x^2-6x-3\)
\(=3\left(3x^2-2x-1\right)\)
\(=3\left(3x^2-3x+x-1\right)\)
\(=3\left[3x\left(x-1\right)+\left(x-1\right)\right]\)
\(=3\left(x-1\right)\left(3x+1\right)\)
c) \(2x^2-3x-2\)
\(=2x^2-4x+x-2\)
\(=\left(2x^2-4x\right)+\left(x-2\right)\)
\(=2x\left(x-2\right)+\left(x-2\right)\)
\(=\left(2x+1\right)\left(x-2\right)\)
d) \(3x^2+x-2\)
\(=3x^2+3x-2x-2\)
\(=\left(3x^2+3x\right)-\left(2x+2\right)\)
\(=3x\left(x+1\right)-2\left(x+1\right)\)
\(=\left(x+1\right)\left(3x-2\right)\)
e) \(3x^2+10x+3\)
\(=3x^2+9x+x+3\)
\(=3x\left(x+3\right)+\left(x+3\right)\)
\(=\left(x+3\right)\left(3x+1\right)\)
a)x2-5x+6=(x2-2x)-(3x-6)=x(x-2)-3(x-2)(=(x-2)(x-3)
b)x2+5x+6=(x2+2x)+(3x+6)=x(x+2)+3(x+2)=(x+2)(x+3)
c)x2-7x+12=(x2-3x)-(4x-12)=x(x-3)-4(x-3)=(x-3)(x-4)
d)x2+7x+12=(x2+3x)+(4x+12)=x(x+3)+4(x+3)=(x+3)(x+4)
a) x2 + x - 12 = x2 - 3x + 4x - 12 = x(x - 3) + 4(x - 3) = (x - 3)(x + 4)
b) x2 - x - 12 = x2 + 3x - 4x - 12 = x(x + 3) - 4(x + 3) = (x + 3)(x - 4)
c) x2 - 9x + 20 = x2 - 4x - 5x + 20 = x(x - 4) - 5(x - 4) = (x - 4)(x - 5)
d) x2 + 9x + 20 = x2 + 4x + 5x + 20 = x(x + 4) + 5(x + 4) = (x + 4)(x + 5)
a,x^2+x-12=x^2-3x+4x-12
=x(x-3)+4(x-3)
=(x-3)*(x+4)
b) x2 - x - 12 = x2 + 3x - 4x - 12 = x(x + 3) - 4(x + 3) = (x + 3)(x - 4)
\(1,\)
\(x^2+x-12\)
\(=x^2-3x+4x-12\)
\(=x\left(x-3\right)+4\left(x-3\right)\)
\(=\left(x+4\right)\left(x-3\right)\)
\(2,\)
\(x^2-9x+20\)
\(=x^2-4x-5x+20\)
\(=x\left(x-4\right)-5\left(x-4\right)\)
\(=\left(x-5\right)\left(x-4\right)\)
\(3,\)
\(x^2+x-20\)
\(=x^2-4x+5x-20\)
\(=x\left(x-4\right)+5\left(x-4\right)\)
\(=\left(x+5\right)\left(x-4\right)\)
4x^2 - 7x -2 = 4x^2 - 8x + x - 2 = 4x(x - 2) + (x - 2) = (x -2)(4x + 1)
a) x2 + x - 20 = x2 - 4x + 5x - 20 = x(x - 4) + 5(x - 4) = (x - 4)(x + 5)
b) x2 - x - 20 = x2 + 4x - 5x - 20 = x(x + 4) - 5(x + 4) = (x + 4)(x - 5)
c) 2x2 - 3x - 2 = 2x2 - 4x + x - 2 = 2x(x - 2) + (x - 2) = (x - 2)(2x + 1)
d) 3x2 + x - 2 = 3x2 + 3x - 2x - 2 = 3x(x + 1) - 2(x + 1) = (x + 1)(3x - 2)
Cách 1:
Ta có: x2 – x – 12 = x2 – x – 16 + 4
= (x2 – 16) – (x – 4)
= (x – 4).(x + 4) – (x – 4)
= (x – 4).(x + 4 – 1)
= (x – 4).(x + 3)
Cách 2:
x2 – x – 12 = x2 – x – 9 – 3
= (x2 – 9) – (x + 3)
= (x – 3).(x + 3) – (x + 3)
= (x + 3).(x – 4)
Cách 3:
x2 – x – 12 = x2 – 4x + 3x – 12
= (x2 – 4x) + (3x – 12)
= x.(x – 4) + 3.(x – 4)
= (x – 4).(x + 3).
Chúc bạn hk tốt nha.Nhớ cho mik nhé bạn