giúp mk với ai xong  trước mk k cho nha

\(A=\dfrac{1}{101}+\dfrac{2}{101}+\dfrac{3}{101}+...+\dfrac{99}{101}+\dfrac{100}{101}\)
\(=\dfrac{1+2+3+...+99+100}{101}\)
Đặt \(B=1+2+3+...+99+100\)
Số số hạng của B là:
\(\left(100-1\right):1+1=100\left(số\right)\)
Tổng của B:
\(\dfrac{\left(1+100\right)\times100}{2}=5050\)
\(\Rightarrow A=\dfrac{1+2+3+...+99+100}{101}\)
\(=\dfrac{B}{101}\)
\(=\dfrac{5050}{101}=50\)
Vậy \(A=50\)

50

101.(-162)+38(-101)+101

= 101.(-162)-38.101+101=101.(-162-38+1)=101.(-199)=-20099

17,8 x 101 - 1

=(17,8 x 101) - 1

= 1797, 8 - 1

=1796,8 

\(17,8\times101-1=1797,8-1=1796,8\)

100 S

101 Đ          

95 S

Tham Khảo:https://olm.vn/hoi-dap/detail/10864465705.html

\(M=\frac{\left(101+1\right)101}{2}:\left[\left(101-100\right)+.....+\left(3-2\right)+1\right]\)

\(\Rightarrow M=\frac{102.101}{2}:\left(1+1+...+1\right)\)

\(\Rightarrow M=\frac{102.101}{2}:51\)

\(\Rightarrow M=\frac{51.2.101}{51.2}\)

\(\Rightarrow M=101\)

\(M=\left(101+100+.....+2+1\right):\left(101-100+.........-2+1\right)\)

\(M=\frac{\left(101+1\right).101}{2}:\left\{\left(101-100\right)+.......+\left(3-2\right)+1\right\}\)

\(M=5151:\left\{1+1+......+1+1\right\}\)

\(M=5151:51\\ M=101\)

\(101\times0,128-0,128=12,928-0,128=12,8\)

\(101\times1,196-1,996=120,796-1,996=118,8\)