a) Đúng

b) Sai

c) Đúng

a) Đ

b) S

c) Đ

a. Đ

b. S

a. 96 : 8 : 2 = 6

96 : ( 8 x 2 ) = 6

96 : 8 : 2 = 96 : ( 8 x 2 )

b. 81 : 9 : 3 = 3

81 : ( 9 x 3 ) = 3

81 : 9 : 3 = 81 : ( 9x 3)

2^x+2-2^x=96

=>2^x\(\cdot\)2²-2^x=96

=>2^x(2²-1)=96

=>2^x\(\cdot\)3=96

=>2^x=96:3=32=2⁵

=>x=5

Vậy x=5

`@` `\text {Ans}`

`\downarrow`

\(2^{x+2}-2^x=96?\)

`\Rightarrow 2^x . 2^2 - 2^x = 96`

`\Rightarrow 2^x . (2^2 - 1) = 96`

`\Rightarrow 2^x . 3 = 96`

`\Rightarrow 2^x = 96 \div 3`

`\Rightarrow 2^x =32`

`\Rightarrow 2^x = 2^5`

`\Rightarrow x = 5`

Vậy, `x = 5.`

\(2^{x+2}-96=2^x\)\(\Leftrightarrow2^{x+2}-2^x=96\)

\(\Leftrightarrow2^x\left(2^2-1\right)=96\)\(\Leftrightarrow2^x.3=96\)

\(\Leftrightarrow2^x=32=2^5\)\(\Leftrightarrow x=5\)

Vậy \(x=5\)

2^{x + 2} - 96 = 2^x

=> 2^{x + 2} - 2^x = 96

=> 2^x.2² - 2^x = 96

=> 2^x-(2² - 1) = 96

=> 2^x.3 = 96

=> 2^x = 32

=> x = 5

Vậy x = 5

\(2^{x+2}-2^x=96\)

\(\Leftrightarrow2^x\cdot2^2-2^x=96\)

\(\Leftrightarrow2^x\left(2^2-1\right)=96\)

\(\Leftrightarrow2^x\cdot3=96\)

\(\Leftrightarrow2^x=96\div3\)

\(\Leftrightarrow2^x=32\)

\(\Leftrightarrow2^x=2^5\)

\(\Leftrightarrow x=5\)

Vậy x = 5 

 2^(x+2) - 2^x = 96 
<=> (2^x)(2^2) -2^x = 96 
(2^x)[(2^2) -1)] = 96 
2^x = 96/3 = 32 
2^5 = 32 
Đáp số: 
x = 5 

​chúc bn hok tốt

\(2^{x+2}-2^x=96\)

\(2^x.\left(2^2-1\right)=96\)

\(2^x.3=96\)

\(2^x=32\)

\(2^x=2^5\)

\(\Rightarrow x=5\)

\(2^{x+2}-2^x=96\)   

\(2^x\left(2^2-1\right)=96\)   

\(2^x\left(4-1\right)=96\)   

\(2^x\cdot3=96\)   

\(2^x=96:3\)   

\(2^x=32\)   

\(2^x=2^5\)   

\(x=5\)