Tìm x biết:
2^ x+2+2^ x-1+2^ x-2=152
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Trl:
a) \(x+x+x+91=-2\)
\(\Rightarrow x.3+91=-2\)
\(\Rightarrow x.3=-2-91\)
\(\Rightarrow x.3=-93\)
\(\Rightarrow x=-93:3\)
\(\Rightarrow x=-31\)
b) \(-125-\left(3x+1\right)=-2.27\)
\(\Rightarrow-125-\left(3x+1\right)=-54\)
\(\Rightarrow\left(3x+1\right)=-125-\left(-54\right)\)
\(\Rightarrow\left(3x+1\right)=-125+54\)
\(\Rightarrow\left(3x+1\right)=-71\)
\(\Rightarrow3x=-71-1\)
\(\Rightarrow3x=-72\)
\(\Rightarrow x=-72:3\)
\(\Rightarrow x=-24\)
Hc tốt
2x + 2 + 2x - 1 + 2x - 2 = 152
19 . 2x - 2 = 152
19 . 2x - 2/19 = 152/19
2x - 2 = 8
2x - 2 = 23
x - 2 = 3
x = 3 + 2
x = 5
\(2x+3=15\\ \Rightarrow2x=15-3=12\\ \Rightarrow x=\dfrac{12}{2}=6\\ ---\\ 28-3x=13\\ \Rightarrow3x=28-13=15\\ \Rightarrow x=\dfrac{15}{3}=5\\ ---\\ \left(x-1954\right).5=50\\ \Rightarrow x-1954=50:5=10\\ \Rightarrow x=10+1954=1964\\ ---\\ x-152:2=46\\ \Rightarrow x-76=46\\ \Rightarrow x=46+76=122\)
a, 2\(x\) + 3 = 15
2\(x\) = 12
\(x\) = 6
b, 28 - 3\(x\) = 13
3\(x\) = 28 - 13
3\(x\) = 15
\(x\) = 5
Bài 1:
a: Ta có: \(48751-\left(10425+y\right)=3828:12\)
\(\Leftrightarrow y+10425=48751-319=48432\)
hay y=38007
b: Ta có: \(\left(2367-y\right)-\left(2^{10}-7\right)=15^2-20\)
\(\Leftrightarrow2367-y=1222\)
hay y=1145
Bài 2:
Ta có: \(8\cdot6+288:\left(x-3\right)^2=50\)
\(\Leftrightarrow288:\left(x-3\right)^2=2\)
\(\Leftrightarrow\left(x-3\right)^2=144\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\)
`a,`
`x*3+7=16`
`=>3x = 16 - 7`
`=> 3x = 9`
`=> x = 9 \div 3`
`=> x = 3`
Vậy, `x = 3`
`b,`
` x- 152 \div 2 = 46?`
`=> x - 76 = 46`
`=> x = 46 + 76`
`=> x = 122`
Vậy, `x = 122.`
`c,`
` 74-2*(x+3)=34`
`=> 2(x + 3) = 74 - 34`
`=> 2(x+2) = 40`
`=> x + 2 = 40 \div 2`
`=> x + 2 = 20`
`=> x = 20 - 2`
`=> x = 18`
Vậy, `x = 18.`
\(2^{x+2}+2^{x-1}+2^{x-2}=152\)
=> \(2^x.2^2+2^x:2+2^x:2^2=152\)
=> \(2^x.2^2+2^x.\frac{1}{2}+2^x.\frac{1}{4}=152\)
=> \(2^x.(4+\frac{1}{2}+\frac{1}{4})=152\)
=> \(2^x.\frac{19}{4}=152\)
=> \(2^x=32\)
=> \(2^x=2^5\)
=> x = 5