Mn khoanh giúp mk nka !!!

1. C

2. C

3. C

C1: \(\left(x-1\right)^2=5^4=625\)

\(\Rightarrow\left[{}\begin{matrix}x-1=25\\x-1=-25\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=26\\x=-24\end{matrix}\right.\) => Chọn C

C2: \(\left(4x^2-9\right)\left(2^{x-1}-1\right)=0\)

\(\Rightarrow\left(2x-3\right)\left(2x+3\right)\left(2^{x-1}-1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{2}\\x-1=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{2}\\x=1\end{matrix}\right.\) => Chọn A

C3: \(3^x=9^3.27^5\)

\(\Rightarrow3^x=3^6.3^{15}=3^{21}\Rightarrow x=21\) => Chọn B

Cảm ơn bn !!!

\(\left(y-\frac{2}{5}\right):\frac{4}{3}=\frac{3}{8}\)

\(y-\frac{2}{5}=\frac{3}{8}.\frac{4}{3}\)

\(y-\frac{2}{5}=\frac{1}{2}\)

\(y=\frac{1}{2}+\frac{2}{5}\)

\(\Rightarrow y=\frac{9}{10}\)

\(y.\frac{5}{6}=\frac{1}{4}+\frac{1}{3}\)

\(y.\frac{5}{6}=\frac{7}{12}\)

\(y=\frac{7}{12}:\frac{5}{6}\)

\(y=\frac{7}{12}.\frac{6}{5}\)

\(\Rightarrow y=\frac{7}{10}\)

a ) \(\left(y-\frac{2}{5}\right):\frac{4}{3}=\frac{3}{8}\)

   \(\left(y-\frac{2}{5}\right)=\frac{3}{8}\times\frac{4}{3}\)

     \(y-\frac{2}{5}=\frac{1}{2}\)

                 \(y=\frac{1}{2}+\frac{2}{5}\)

                \(y=\frac{5}{10}+\frac{4}{10}\)

                 \(y=\frac{9}{10}\)

 Vậy \(y=\frac{9}{10}\)

b ) \(y\times\frac{5}{6}=\frac{1}{4}+\frac{1}{3}\)

\(y\times\frac{5}{6}=\frac{3}{12}+\frac{4}{12}\)

\(y\times\frac{5}{6}=\frac{7}{12}\)

           \(y=\frac{7}{12}:\frac{5}{6}\)

          \(y=\frac{7}{12}\times\frac{6}{5}\)

        \(y=\frac{7}{10}\)

Vậy \(y=\frac{7}{10}\)

Chúc bạn học tốt !!!

|3x-1|=7/6

=>3x-1=-7/6 hoặc 7/6

• Với 3x-1=-7/6

=>3x=-1/6

=>x=-1/18

• Với 3x-1=7/6

=>3x=13/6

=>x=13/18

b)5/3*|x-1/2|+1/3=4/3

=>5/3*|x-1/2|=1

=>|x-1/2|=3/5

=>x-1/2=-3/5 hoặc 3/5

• Với x-1/2=-3/5

=>x=-1/10

• Với x-1/2=3/5

=>x=11/10

Câu 1: C

Câu 2: A

1c . 2a

1/n=5

chỉ biết vậy thôi !!!!