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C = 1 - 2 - 3 + 4 + 5 - 6 - 7 - 8 + ... + 2013 - 2014 - 2015 + 2016 + 2017 - 2018

Số số hạng của C từ 1 đến 2016 là : ( 2016 - 1 ) : 1 + 1 = 2016 số

Nhóm 4 số thành 1 cặp ta có : 2016 : 4 = 504 cặp

=> C = ( 1 - 2 - 3 + 4 ) + ( 5 - 6 - 7 + 8 ) + ... + ( 2013 - 2014 - 2015 + 2016 ) + 2017 - 2018

C = 0 + 0 + ... + 0 + ( -1 )

C = -1

S=\(3\left(1+\frac{1}{1+2}+\frac{1}{1+2+3}+...+\frac{1}{1+2+3+...+100}\right)\)

\(S=3\left(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{5050}\right)\)

\(S=3.\frac{1}{2}\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{10100}\right)\)

\(S=\frac{3}{2}\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{100.101}\right)\)

\(S=\frac{3}{2}\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{100}-\frac{1}{101}\right)\)

\(S=\frac{3}{2}\left(1-\frac{1}{101}\right)\)

\(S=\frac{3}{2}.\frac{100}{101}=\frac{150}{101}\)

S = 3 + 1 + 1/2 +....

\(B=1.2.3+2.3.4+3.4.5+.......+49.50.51\)

\(\Rightarrow4B=1.2.3.4+2.3.4.4+3.4.5.4+.......+49.50.51.4\)

\(=1.2.3.4+2.3.4\left(5-1\right)+3.4.5\left(6-2\right)+.........+49.50.51.\left(52-48\right)\)

\(=1.2.3.4+2.3.4.5-1.2.3.4+3.4.5.6-2.3.4.5+.........+49.50.51.52-48.49.50.51\)

\(=49.50.51.52\)

\(\Rightarrow B=\frac{49.50.51.52}{4}=1624350\)

= (2/5 + 3/5) + (6/9 + 1/3) + (7/4 + 1/4)

= 1 + (6/9 + 3/9) + 2 = 1 + 1 + 2 = 4

\(\dfrac{2}{5}+\dfrac{6}{9}+\dfrac{7}{4}+\dfrac{3}{5}+\dfrac{1}{3}+\dfrac{1}{4}\\ =\left(\dfrac{2}{5}+\dfrac{3}{5}\right)+\left(\dfrac{7}{4}+\dfrac{1}{4}\right)+\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\\ =1+2+1=4\)

5⁶ : 5⁴ + 2³ . 2² - 1²⁰¹⁷

=5\(^2\)+ 2\(^5\)- 1\(^{2017}\)

=56

5⁶:5⁴+2³.2²-1²⁰¹⁷

=5²+2⁵-1

=25+32-1

=56

\(B=\left(\dfrac{5}{2019}+\dfrac{4}{2020}-\dfrac{3}{2021}\right)\cdot\dfrac{3-2-1}{6}=0\)

\(a,1\dfrac{4}{7}.3\dfrac{4}{11}.3\dfrac{11}{15}.5\dfrac{5}{8}\)

\(=\dfrac{11}{7}.\dfrac{27}{11}.\dfrac{56}{15}.\dfrac{45}{8}\)

\(=\dfrac{11.27.56.45}{7.11.15.8}\)

\(=\dfrac{1.3.7.3}{1.1.1.1}\)

\(=63\)

\(b,\dfrac{3}{4}.1\dfrac{1}{2}+\dfrac{3}{4}.\dfrac{1}{2}\)

\(=\dfrac{3}{4}.\left(1\dfrac{1}{2}+\dfrac{1}{2}\right)\)

\(=\dfrac{3}{4}.2\)

\(=\dfrac{3}{2}\)

Thực hiện phép tính ( bằng cách hợp lí nếu có thể ) 

A. 2/3 - (- 1/4)+3/5-(+7/45)-(-5/9)+1/12+1/39 

B. 6.(-2/3)^2 - 3(-2/3)^2 - 2 : (-3/2)+4