\(_{\left|3x-5\right|=2009\left(2010^{2009}+2010^{2008}+...+2010+1\right)-2010^{2010}+5}\)

|3x-5|=2009(2010^2009+2010^2008+....+2010+1)-2010^2010=5

So sánh các giá trị \(A=\left(19^{2009}+5^{2009}\right)^{2010}\&B=\left(19^{2010}+5^{2010}\right)^{2009}.\)

So sánh giá trị của \(A=\left(19^{2009}+5^{2009}\right)^{2010}\&B=\left(19^{2010}+5^{2010}\right)^{2009}.\)

\(\frac{\left(2009-x\right)^2+\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}{\left(2009-x\right)^2-\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}=\frac{19}{49}\)

tìm x :

\(\frac{\left(2009-x\right)^2+\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}{\left(2009-x\right)^2-\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}=\frac{49}{19}\)

tìm x biết \(\frac{\left(2009-x\right)^2+\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}{\left(2009-x\right)^2-\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}=\frac{19}{49}\)

Giải phương trình:

\(\left(x-2008\right)^{2010}+\left(x-2009\right)^{2010}=1\)

Tìm x biết:

\(\frac{\left(2009-x\right)^2+\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}{\left(2009-x\right)^2-\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}=\frac{19}{49}\)