\(\frac{15}{41}+\frac{-138}{41}\le x< \frac{1}{2}+\frac{1}{3}+\frac{1}{6}\)

\(\Leftrightarrow-3\le x< 1\)

\(\Leftrightarrow x\in\left\{-3;-2;-1;0\right\}\)

\(\frac{15}{41}+\frac{-138}{41}\le x< \frac{1}{2}+\frac{1}{3}+\frac{1}{6}\)

\(\Rightarrow\frac{15+(-138)}{41}\le x< \frac{1\cdot3}{6}+\frac{1\cdot2}{6}+\frac{1}{6}\)

\(\Rightarrow\frac{-123}{41}\le x< \frac{3}{6}+\frac{2}{6}+\frac{1}{6}\)

\(\Rightarrow-3\le x< 1\Leftrightarrow x\in\left\{-3;-2;-1;0\right\}\)

\(\frac{15}{41}+\frac{-138}{41}\le x< \frac{1}{2}+\frac{1}{3}+\frac{1}{6}\)

\(\Rightarrow-3\le x< 1\)

\(\Rightarrow-3\le-3;-2;-1;0< 1\)
\(\Rightarrow x\in\left\{-3;-2;-1;0\right\}\)

~ Hok tốt ~

\(\frac{15}{41}+\frac{-138}{41}< x< \frac{1}{2}+\frac{1}{3}+\frac{1}{6}\)

\(\Leftrightarrow\frac{-123}{41}< x< \frac{1.3+1.2+1}{6}\)

\(\Leftrightarrow-3< x< 1\)

\(\Rightarrow x\in\left\{-2;-1;0\right\}\)

\(\frac{x}{5}=\frac{15}{2}-\frac{51}{10}\)

\(\frac{x}{5}=\frac{15.5-51}{10}\)

\(\frac{x}{5}=\frac{24}{10}\)

\(\frac{x}{5}=\frac{12}{5}\)

\(x=12\)

gửi đến bạn vũ thì gửi cho bạn đấy chứ đăng lên đây làm gì.

đỗ công tùng đúng đó đăng làm j

a) \(-4\frac{3}{5}\cdot2\frac{4}{23}\le x\le-2\frac{3}{15}:1\frac{6}{15}\)

=> \(-\frac{23}{5}\cdot\frac{50}{23}\le x\le\frac{-33}{15}:\frac{21}{15}\)

=> \(-10\le x\le\frac{-11}{7}\)

=> \(x\in\left\{-10;-9,-8,-7,-6,-5,-4,-3,-2,-1\right\}\)

Thực hiện phép tính ( bằng cách hợp lí nếu có thể):

a, \(5\frac{4}{13}.15\frac{3}{41}-5\frac{4}{13}.2\frac{3}{41}\)

\(=5\frac{4}{13}\left(15\frac{3}{41}-2\frac{3}{41}\right)\)

\(=15\frac{4}{13}\left(\frac{618}{41}-\frac{85}{41}\right)\)

\(=\frac{69}{13}.13\)

\(=69\)

b, \(6.\left(-\frac{1}{3}\right)^2-\left(\frac{1}{4}:2-\frac{7}{16}.\frac{-4}{21}\right)\)

\(=6.\frac{1}{9}-\left(\frac{1}{8}-\frac{-1}{12}\right)\)

\(=\frac{2}{3}-\left(\frac{3}{24}-\frac{-2}{24}\right)\)

\(=\frac{2}{3}-\frac{5}{24}\)

\(=\frac{16}{24}-\frac{5}{24}\)

\(=\frac{11}{24}\)

Chúc bạn hok tốt!!! lưu khánh huyền

kcj