Lời giải:

$x+x\times \frac{1}{4}: \frac{2}{7}+x: \frac{2}{9}=255$

$x+x\times \frac{7}{8}+x\times \frac{9}{2}=255$

$x\times (1+\frac{7}{8}+\frac{9}{2})=255$

$x\times \frac{51}{8}=255$

$x=255: \frac{51}{8}=40$

\(\frac{1}{2}\left(\frac{4}{9}-x\right)-\frac{3}{2}\left(16-x\right)+\frac{1}{2}\left(5x+10\right)=0\)

\(\Leftrightarrow\frac{2}{9}-\frac{1}{2}x-24+\frac{3}{2}x+\frac{5}{2}x+5=0\)

\(\Leftrightarrow-\frac{169}{9}=\frac{7}{2}x\Leftrightarrow x=-\frac{338}{63}\)

Sai thì thông cảm cho mk nha

la 0 nha

a: \(\Leftrightarrow\left(2-x\right)\left(x-3\right)+\left(x-1\right)\left(x+3\right)=-4x\)

\(\Leftrightarrow2x-6-x^2+3x+x^2+3x-x-3=-4x\)

=>7x-9=-4x

=>11x=9

hay x=9/11

b: \(\Leftrightarrow\left(5-x\right)\left(x-4\right)+\left(x+2\right)\left(x+4\right)=-3x\)

\(\Leftrightarrow5x-20-x^2+4x+x^2+6x+8=-3x\)

=>15x-12=-3x

=>18x=12

hay x=2/3

tự tính nhẩm bằng 1

\(( 7x-19)-(5x-12)=3x-(9-2x)-1\)

\(<=> 7x-19-5x+12=3x-9+2x-1\)

\(<=> 2x-7=5x-10\)

\(<=> 2x-5x=-10+7\)

\(<=> -3x = -3\)

\(<=> x=3\)

1) (-1)³ + (-2)³ + (-3)³ - |x+5| = (5 - 6 -7)³

     (-1) -8 - 27 - |x+5| = -512

                         |x+5| = 476

=> x + 5 = 476 hoặc x + 5 = -476

     =>  x = 472           => x = -481

Vậy....

2) [(x-3)² - 9] . [(x-1)²-1]=0

    ( x - 3 - 3).(x - 3 + 3).(x - 1 - 1).(x - 1 +1) =0

    ( x - 6) . (x - 0) . (x - 2) . (x - 0) = 0

=> x - 6 = 0           hoặc        x - 0 = 0           hoặc x - 2 = 0

     => x = 6                            => x = 0                   => x = 2

Vậy...

\(a)\frac{3}{5}\times\frac{2}{5}+\frac{3}{4}\times\frac{3}{5}\)

\(=\frac{3}{5}\times\left(\frac{2}{5}+\frac{3}{4}\right)\)

\(=\frac{3}{5}\times\left(\frac{8}{20}+\frac{15}{20}\right)\)

\(=\frac{3}{5}\times\frac{23}{20}\)

\(=\frac{69}{100}\)

\(b)\frac{5}{9}\times\frac{7}{3}\times\frac{9}{5}\)

\(=\left(\frac{5}{9}\times\frac{9}{5}\right)\times\frac{7}{3}\)

\(=1\times\frac{7}{3}\)

\(=\frac{7}{3}\)

a) 3/5x2/5+3/4x3/5

=2/5+3/4x(3/5)

=69/100

.B chịu

tích cho t nha

bảo lm hộ mà chưa lm đã đòi tích

tham khảo:

99/100