yutyugubhujyikiu

a)

\(\begin{array}{l}A = \frac{5}{{11}}.\left( {\frac{{ - 3}}{{23}}} \right).\frac{{11}}{5}.\left( { - 4,6} \right)\\A = \frac{5}{{11}}.\left( {\frac{{ - 3}}{{23}}} \right).\frac{{11}}{5}.\frac{{ - 23}}{5}\\A = \frac{{5.\left( { - 3} \right).11.\left( { - 23} \right)}}{{11.23.5.5}}\\A = \frac{3}{5}\end{array}\)  

b)

\(\begin{array}{l}B = \left( {\frac{{ - 7}}{9}} \right).\frac{{13}}{{25}} - \frac{{13}}{{25}}.\frac{2}{9}\\B = \frac{{13}}{{25}}.\left( {\frac{{ - 7}}{9} - \frac{2}{9}} \right)\\B = \frac{{13}}{{25}}.(-1)\\B = \frac{{-13}}{{25}}.\end{array}\)

\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{13}{12}:3\)

= \(\frac{28}{15}.\frac{3}{4}-\left(\frac{104}{195}+\frac{1}{4}\right).\frac{24}{47}-\frac{49}{12}.\frac{1}{3}\)

= \(\frac{4.3.7}{4.3.5}-\frac{47}{60}.\frac{24}{47}-\frac{49}{36}\)

= \(\frac{7}{5}-\frac{2}{5}-\frac{49}{36}\)

= \(1-\frac{49}{36}\)

= \(-\frac{13}{36}\)

Chúc bạn làm bài tốt

\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{27}-3\frac{13}{12}:3\)

=\(\frac{28}{15}.\frac{3}{4}-\left(\frac{8}{15}+\frac{1}{4}\right).\frac{24}{47}-\frac{49}{12}.\frac{1}{3}\)

=\(\frac{7}{5}-\frac{47}{60}.\frac{24}{47}-\frac{49}{36}\)

=\(\frac{7}{5}-\frac{2}{5}-\frac{49}{36}\)

=\(\frac{-13}{36}\)

\(1\frac{13}{15}\cdot\left(0.5\right)^2\cdot\left|-3\right|+\left(\frac{8}{15}-25\%\right):1\frac{23}{24}\)

\(=\frac{28}{15}\cdot\frac{1}{4}\cdot3+\left(\frac{8}{15}-\frac{1}{4}\right)\cdot\frac{47}{24}\)

\(=\frac{28\cdot1\cdot3}{15\cdot4}+\frac{17}{60}\cdot\frac{47}{24}\)

\(=\frac{21}{25}+\frac{799}{1440}=\frac{10043}{7200}\)

a)\(\frac{6}{14}+\frac{8}{-36}-\frac{5}{35}=\frac{3}{7}+\frac{2}{-9}-\frac{1}{7}=\frac{2}{7}+\frac{2}{-9}=\frac{-18+14}{-63}=\frac{4}{63}\)

Sửa 41 -> 1/41 nhé!!nhầm xíu :>>

thank bạn <3

\(-\frac{2000}{139}\)