Ta có B = 1² + 2² + 3² + ... + 98²

= 1.1 + 2.2 + 3.3 + ... + 98.98

= 1.(2 - 1) + 2.(3 - 1) + 3.(4 - 1) + ... + 98.(99 - 1)

= 1.2 + 2.3 + 3.4 + ... + 98.99 - (1 + 2 + 3 + ... + 98)

=  1.2 + 2.3 + 3.4 + ... + 98.99 - 98.(98 + 1) : 2

=  1.2 + 2.3 + 3.4 + ... + 98.99 -  4851

Khi đó B - A = (1.2 + 2.3 + 3.4 + ... + 98.99 -  4851) - 1.2 + 2.3 + 3.4 + ... + 98.99

                    = 1.2 + 2.3 + 3.4 + ... + 98.99 - 4851 - 1.2 + 2.3 + 3.4 + ... + 98.99

                     = -4851

Vậy B - A = - 4851

bai toan nay giai dai lam

Đặt \(A=\frac{1}{3^2}+\frac{1}{4^2}+\frac{1}{5^2}+....+\frac{1}{98^2}\)

Ta có : \(A< \frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{97.98}\)

\(A< \frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{97}-\frac{1}{98}\)

\(A< \frac{1}{2}-\frac{1}{98}\)

\(A< \frac{1}{2}\)

GOOD LUCK !!!

ddddddddddddddddd

A=-1++(-1)+..+-(1) có 50 số -1

=>A=-1x50=-50

B=(1-2-3+4)+(5-6-7+8)+...+(97-98-99+100)

B=0+0+0+..+0

B=0

C=2^100-(2^99+2^98+...+1)

C=2^100-(2^100-1)

C=1

ta có 

\(B=1+\left(1-\frac{1}{2}\right)+..+\left(1-\frac{1}{100}\right)\)

\(=1+\frac{1}{2}+\frac{2}{3}+..+\frac{99}{100}=A\)

Vậy A=B