Theo mình là : \(A< B\)

\(A=1-\frac{1}{2014x2015}\)

\(B=1-\frac{1}{2015x2016}\)

\(2014x2015< 2015x2016\Rightarrow\frac{1}{2014x2015}>\frac{1}{2015x2016}\Rightarrow A< B\)

\(A=\frac{2015\times2016-1}{2014\times2015+2016}\)

\(A=\frac{2015\times2016}{2014\times2015}+\frac{1}{2016}\)

\(A=\frac{1008}{1007}+\frac{1}{2006}\)

\(A=\frac{2023055}{2020042}\)

ban nao giai nhanh minh tk cho

Cau nay kho

so tan cung cua a la chu so 0

=[2013*2014*+2014*2015+2015*2016]*[\(1\frac{1}{3}-1\frac{1}{3}\)]

=A*0

=0

nhớ k nha mấy friends/

what men

x la dau nhan ha em?

x là nhân hả bạn

2014 x 3 + 4028 x 2 + 2014 x 5 - 2014 x 2

= 2014 x 3 + 2014 x 2 x 2 + 2014 x 5 - 2014 x 2

= 2014 x 3 + 2014 x 4 + 2014 x 5 - 2014 x 2

= 2014 x ( 3 + 4 + 5 - 2 )

= 2014 x 10 = 20140

\(2014\text{×}3+4028\text{×}2+2014\text{×}5-2014\text{×}2\\ =2014\text{×}3+2014\text{×}2\text{×}2+2014\text{×}5-2014\text{×}2\\ =2014\text{×}3+2014\text{×}4+2014\text{×}5-2014\text{×}2\\ =2014\text{×}\left(3+4+5-2\right)=2014\text{×}10=20140\)

vì 1/1*2=1-1/2

   1/2*3=1/2-1/3

.....................

1/2014*2015=1/2014-1/2015

=1-1/2+1/2-1/3+1/3-....+1/2014-1/2015

=1-1/2015

=2014/2115

\(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+....+\frac{1}{2014x2015}\)

=\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{99}-\frac{1}{100}\)

=\(1-\frac{1}{100}\)

=\(\frac{99}{100}\)