Đề bài tự viết ...

 2004 x 37 + 2004 x 2 + 2004 x 59 + 2004 x 1 / 334 x 321 - 201 x 334 - 334 x 102 - 17 x 334

= 2004 x ( 37 + 2 + 59 + 1 ) / 334 x ( 321 - 201 - 102 - 17 )

= 2004 x 99 / 334 x 1

= 198396 / 334

= 594

# Chúc bạn học tốt #

2004 x 37 + 2004 x 2 + 2004 x 59 +2004 / 334 x 321 -201 x 334 - 334 x 102 - 17 x 334

  Trả lời: (Cứ cho là 2 vế a ,b nhé bạn!!!)

A)       2004 x 37 + 2004 x 2 + 2004 x 59 +2004

=     2004 x 37  + 2004 x 2 + 2004 x 59 + 2004 x 1

=     2004 x( 37 + 2 + 59 + 1)

=     2004 x 100

=     200400

B)   334 x 332 - 201 x 334 - 334 x 102 - 17 x 334

=     334 x (332 - 201 - 102 - 17 )

=     334 x 12

= 4008

             *Mình chắc chắn đúng 100% nhé!!!

                                                      #Trúc Mai

1.9056

2.129006

3.584146200000

4.19007388

lời giải nữa nhé

a) X +  5 9 =  3 2   ⇒ X =  3 2 - 5 9 = 27 18 - 10 18 = 17 18 .

b) X +  1 1 2   =   3 3 4   ⇒ X =  3 3 4 - 1 1 2 = 15 4 - 3 2 = 9 4 .

a)\(2x^3+7x^2+7x+2=0\)

\(\Leftrightarrow2\cdot\left(x^3+1\right)+7x\cdot\left(x+1\right)=0\)

\(\Leftrightarrow2\cdot\left(x+1\right)\cdot\left(x^2+x+1\right)+7x\cdot\left(x+1\right)=0\)

\(\Leftrightarrow\left(x+1\right)\cdot\left[2\cdot\left(x^2+x+1\right)+7x\right]=0\)

\(\Leftrightarrow\left(x+1\right)\cdot\left(2x^2-2x+2+7x\right)=0\)

\(\Leftrightarrow\left(x+1\right)\cdot\left(2x^2+5x+2\right)=0\)

\(\Leftrightarrow\left(x+1\right)\cdot\left(2x+1\right)\cdot\left(x+2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x+1=0\\2x+1=0\\x+2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-1\\x=\frac{-1}{2}\\x=-2\end{matrix}\right.\)

b)\(\frac{x+1}{65}+\frac{x+3}{63}=\frac{x+5}{61}+\frac{x+7}{59}\)

\(\Leftrightarrow\frac{x+1}{65}+\frac{x+3}{63}-\frac{x+5}{61}-\frac{x+7}{59}=0\)

\(\Leftrightarrow\left(\frac{x+1}{65}+1\right)+\left(\frac{x+3}{63}+1\right)-\left(\frac{x+5}{61}+1\right)-\left(\frac{x+7}{59}+1\right)=0\)

\(\Leftrightarrow\frac{x+66}{65}+\frac{x+66}{63}-\frac{x+66}{61}-\frac{x+66}{59}=0\)

\(\Leftrightarrow\left(x+66\right)\cdot\left(\frac{1}{65}+\frac{1}{63}-\frac{1}{61}-\frac{1}{59}\right)=0\)

\(\Rightarrow x+66=0\)

\(\Rightarrow x=-66\)

6) \(2\left(x-8\right)=2^2\)

\(\Rightarrow x-8=2^2:2\)

\(\Rightarrow x-8=2\)

\(\Rightarrow x=2+8\)

\(\Rightarrow x=10\)

tíc mình nha

5) 14 chia hết cho 2x+3

=>2x+3 thuộc ước 14

mà Ư(14)={1,2,7,14}

ta có

vậy x=0