p=12342 x34566+23453

     12342 x(34566+1)+11111

p=12342 x34566+23453

    12342 x34566+12342 x1+11111

p=23453

   12342+11111

p=23453

    23453

p=1

12342+23453/11111

31217

18875 + 12342 = 312117

```pascal
program TimSoNguyenTrongSoN;
uses crt;

procedure TimSoNguyenTrongSoN(n: integer);
var
n_str: string;
so_nguyen_xuat_hien: array of integer;
temp: string;
i, j, so: integer;
begin
n_str := IntToStr(n);
SetLength(so_nguyen_xuat_hien, 0);

for i := 1 to Length(n_str) do
begin
temp := '';
for j := i to Length(n_str) do
begin
temp := temp + n_str[j];
if TryStrToInt(temp, so) then
begin
SetLength(so_nguyen_xuat_hien, Length(so_nguyen_xuat_hien) + 1);
so_nguyen_xuat_hien[Length(so_nguyen_xuat_hien) - 1] := so;
end;
end;
end;

writeln('Cac so nguyen xuat hien trong so ', n, ' la:');
for i := 0 to Length(so_nguyen_xuat_hien) - 1 do
begin
writeln(so_nguyen_xuat_hien[i]);
end;
end;

var
n: integer;
begin
clrscr;
write('Nhap vao so n: ');
readln(n);
TimSoNguyenTrongSoN(n);
readln;
end.
```

sao mình ko chạy được v bạn

\(\frac{x+5}{4x+3}=\frac{10-x}{3y-6}=\frac{x+5+10-x}{4x+3+3y-6}=\frac{15}{4x+3y-3}=\frac{8x-9}{4x+3y-3}\)

\(\Rightarrow8x-9=15\Rightarrow x=3\)

y bằng bao nhiêu hả bn

12342 - 19785 = - 7443

9752 x 49889 = 486 517 528

12342 - 19785 = -7443

9752 x 49889 = 486517528

#)Giải :

Đặt \(A=\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}\)

\(A=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)

\(A=\frac{1}{5}-\frac{1}{10}\)

\(A=\frac{1}{10}\)

cho mk hỏi chút là tại sao ta lấy 1/5 - 1/6 r + 1/6....

\(\frac{x-1986-1987}{1985}+\frac{x-1985-1987}{1986}+\frac{x-1985-1986}{1987}=3\)

=> \(\left(\frac{x-1986-1987}{1985}-1\right)+\left(\frac{x-1985-1987}{1986}-1\right)+\left(\frac{x-1985-1986}{1987}-1\right)=3-3\)

=> \(\frac{x-1985-1986-1987}{1985}+\frac{x-1985-1986-1987}{1986}+\frac{x-1985-1986-1987}{1987}=0\)

=> \(\left(x-1985-1986-1987\right).\left(\frac{1}{1985}+\frac{1}{1986}+\frac{1}{1987}\right)=0\)

=> \(\left(x-5958\right).\left(\frac{1}{1985}+\frac{1}{1986}+\frac{1}{1987}\right)=0\)

Mà \(\frac{1}{1985}+\frac{1}{1986}+\frac{1}{1987}\ne0\)

=> x - 5958 = 0

=> x = 5958

\(a,\frac{12345}{12342}=1+\frac{3}{12342}\)

    \(\frac{23457}{23455}=1+\frac{2}{23455}\)

Vì \(\frac{3}{12342}>\frac{2}{23455}\Rightarrow\frac{12345}{12342}>\frac{23457}{23455}\)

\(b,\frac{149}{150}=1-\frac{1}{150}\)

        \(\frac{4}{11}=1-\frac{7}{11}\)

Vì \(\frac{1}{150}< \frac{7}{11}\Rightarrow\frac{149}{150}>\frac{4}{11}\)

12345/12342 = 1 + 3/12342 = 1 + 1/ 4114 = 1 + 2/8228

23457/23455 = 1 + 2/23455

Có 1 + 2/8228 > 1 + 2/23455 => 12345/12342 > 23457/23455.

149/450 < 150/450 = 1/3

4/11 > 4/12 = 1/3

Vậy 149/450 < 4/11