(- 12) + ( - 13) + 36 + (- 11)
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Lời giải:
$[12+(-57)]-[-67-(-12)]$
$=12-58+67-12=(12-12)+(67-58)=0+9=9$
a: 6/5-2/3=18/15-10/15=8/15
b: 9/7-5/8=72/56-35/56=37/56
c: 7/6-3/4=14/12-9/12=5/12
d: 9/8-8/9=81/72-64/72=17/72
e: 7/5-7/6=7(1/5-1/6)=7/30
f: 3/4-2/5=15/20-8/20=7/20
g: 4/7-5/6=24/42-35/42=-11/41
i: 6/13-5/11=66/143-65/143=1/143
k: 1-4/5=1/5
m: 2-5/9=18/9-5/9=13/9
n: 3-9/5=15/5-9/5=6/5
p: 4-3/4=16/4-3/4=13/4
a) \(\dfrac{6}{5}-\dfrac{2}{3}=\dfrac{18}{15}-\dfrac{10}{15}=\dfrac{8}{15}\)
b) \(\dfrac{9}{7}-\dfrac{5}{8}=\dfrac{72}{56}-\dfrac{35}{56}=\dfrac{37}{56}\)
c) \(\dfrac{7}{6}-\dfrac{3}{4}=\dfrac{28}{24}-\dfrac{18}{24}=\dfrac{10}{24}=\dfrac{5}{12}\)
d) \(\dfrac{9}{8}-\dfrac{8}{9}=\dfrac{81}{72}-\dfrac{64}{72}=\dfrac{17}{72}\)
e) \(\dfrac{7}{5}-\dfrac{7}{6}=\dfrac{42}{30}-\dfrac{35}{30}=\dfrac{7}{30}\)
h) \(\dfrac{4}{7}-\dfrac{5}{6}=\dfrac{24}{42}-\dfrac{35}{42}=-\dfrac{11}{42}\)
i) \(\dfrac{6}{13}-\dfrac{5}{11}=\dfrac{66}{143}-\dfrac{65}{143}=\dfrac{1}{143}\)
k) \(1-\dfrac{4}{5}=\dfrac{5}{5}-\dfrac{4}{5}=\dfrac{1}{5}\)
m) \(2-\dfrac{5}{9}=\dfrac{18}{9}-\dfrac{5}{9}=\dfrac{13}{9}\)
n) \(3-\dfrac{9}{5}=\dfrac{15}{5}-\dfrac{9}{5}=\dfrac{6}{5}\)
p) \(4-\dfrac{3}{4}=\dfrac{16}{4}-\dfrac{3}{4}=\dfrac{13}{4}\)
Ta có:\(\left(-12\right)+\left(-13\right)+36+\left(-11\right)=\left(-12-13-11\right)+36\)
\(=\left(-36\right)+36\)
\(=0\)
(-12)+(-13)+36+(-11)
=[(-12)+(-13)]+(36-11)
=(-25)+25
=0
Chúc bạn học tốt!
#Huyền#