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Lê Nam Phong

nói gì

gọi tổng là S

ta có:S= 4+2²+2³+2⁴+...+2²⁰¹³

2S= 8+2³+2⁴+2⁵+...+2²⁰¹⁴

2S-S= (8+2³+2⁴+2⁵+...+2²⁰¹⁴)-(4+2²+2³+2⁴+...+2²⁰¹³)

 S    =  4+2²⁰¹⁴-4

S     =  2²⁰¹⁴

vậy x=2014

1/2x3/2+1/3x4/2+1/4x5/2+1/5x6/2+.......+2/Xx(X+1)=2011/2013

2/2x3+2/3x4+2/4x5+2/5x6+.....+2/Xx(X+1)=2011/2013

2x(1/2x3+1/3x4+1/4x5+1/5x6+....+1/Xx(x+1)=2011/2013

1/2x3+1/3x4+1/4x5+1/5x6+....+1/Xx(X+1)=2011/4026

1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+.....+ 1/x-1/x+1=2011/4026

1/2-1/x+1=2011/4026

1/x+1=1/2-2011/4026

1/x+1=1/2013

Suy ra x=2012

biết còn hỏi vậy bạn

a) ĐK: \(x\ne4,x\ne2;x\ne-2\)

b) \(A=\dfrac{x^3}{x-4}-\dfrac{x}{x-2}-\dfrac{2}{x+2}\)

\(A=\dfrac{x^3}{\left(x+2\right)\left(x-2\right)}-\dfrac{x\left(x+2\right)}{\left(x+2\right)\left(x-2\right)}-\dfrac{2\left(x-2\right)}{\left(x+2\right)\left(x-2\right)}\)

\(A=\dfrac{x^3-x^2-2x-2x+4}{\left(x+2\right)\left(x-2\right)}\)

\(A=\dfrac{x^3-x^2-4x+4}{\left(x+2\right)\left(x-2\right)}\)

\(A=\dfrac{x^2\left(x-1\right)-4\left(x-1\right)}{\left(x+2\right)\left(x-2\right)}\)

\(A=\dfrac{\left(x-1\right)\left(x^2-4\right)}{x^2-4}\)

\(A=x-1\)

c) \(A=0\) khi:

\(x-1=0\)

\(\Leftrightarrow x=1\left(tm\right)\)

d) A dương khi: \(A>0\)

\(x-1>0\)

\(\Leftrightarrow x>1\)

Kết hợp với đk: 

\(x>1,x\ne4,x\ne2\)

hình như bn nguyễn thị huyền làm sai:

=> 2a -1 thuộc BCNN(3,5,7) = 105

=> 2a =105+1=106

=>a = 106:2 =53

53 nha bn