câu 1
\(a,-8\frac{2}{5}:\left(-2\frac{4}{5}\right)\)
câu 2 tính hợp lý nếu có thể
\(a,15-2\frac{1}{3}:\left(\frac{4}{9}-\frac{1}{6}\right)\)
giúp mik với nhé !!!
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\(\left(\frac{-3}{4}+\frac{2}{5}\right):\frac{3}{7}+\left(\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)
\(=\left(\frac{-3}{4}+\frac{2}{5}+\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)
\(=\left[\left(\frac{-3}{4}+\frac{-1}{4}\right)+\left(\frac{2}{5}+\frac{3}{5}\right)\right]:\frac{3}{7}\)
\(=\left(-1+1\right):\frac{3}{7}\)
\(=0:\frac{3}{7}\)
\(=0\)
Học tốt
a, \(\frac{2}{5}.\frac{1}{3}-\frac{2}{15}:\frac{1}{5}+\frac{3}{5}.\frac{1}{3}\)
\(=\frac{1}{3}.\left(\frac{2}{5}+\frac{3}{5}\right)-\frac{2}{15}.5\)
\(=\frac{1}{3}.1-\frac{2}{3}\)
\(=\frac{1}{3}-\frac{2}{3}\)
\(=\frac{-1}{3}\)
b, \(\left(6-2\frac{4}{5}\right).3\frac{1}{8}+1\frac{3}{8}:\frac{1}{4}\)
\(=\left(6-\frac{14}{5}\right).\frac{25}{8}+\frac{11}{8}.4\)
\(=\frac{16}{5}.\frac{25}{8}+\frac{11}{2}\)
\(=10+\frac{11}{2}\)
\(=\frac{31}{2}\)
1/3×(3/5+2/5)-2/15×1/5
1/3×1-2/15×1/5
1/3-2/15×1/5
1/3-2/75
25/75-2/75
23/75
(6-14/5)×25/8-11/8:4/1
16/5×25/8-11/8:4/1
10/1-11/8:4/1
10/1-11/8×1/4
10/1-11/32
320/32-11/32
309/32
a) A = \(\frac{15}{7}:\left(\frac{1}{15}-\frac{7}{5}\right)-\frac{15}{7}:\left(\frac{17}{15}+\frac{11}{5}\right)=\frac{15}{7}:\frac{-20}{15}-\frac{15}{7}:\frac{50}{15}\)
A = \(\frac{15}{7}.\frac{15}{-20}-\frac{15}{7}.\frac{15}{50}=\frac{15}{7}.\left(\frac{-15}{20}-\frac{15}{50}\right)=\frac{15}{7}.\frac{-105}{100}=-\frac{9}{4}\)
b) B = \(\frac{1}{\left(-\frac{2}{3}\right)^4}.\left(-4\right)^2-1^{2016}-10\frac{1}{3}=\frac{1}{\frac{16}{81}}.16-1-10\frac{1}{3}=\frac{81}{16}.16-1-10\frac{1}{3}\)
B = \(81-1-10-\frac{1}{3}=70-\frac{1}{3}=\frac{209}{3}\)
a) \(\left|-\frac{6}{7}\right|\div\left(-2\right)^3-\sqrt{\frac{9}{16}}\)
\(=\frac{6}{7}\div\left(-8\right)-\frac{3}{4}\)
\(=\frac{-3}{28}-\frac{3}{4}\)
\(=\frac{-6}{7}\)
b) \(-5\frac{5}{9}\div\left(-1\frac{3}{4}\right)+4\frac{5}{9}\div\left(-1\frac{3}{4}\right)\)
\(=\left(-5\frac{5}{9}+4\frac{5}{9}\right)\div\left(-1\frac{3}{4}\right)\)
\(=\left(-5+\frac{5}{9}+4+\frac{5}{9}\right)\div\frac{-7}{4}\)
\(=\left(-1+\frac{10}{9}\right).\frac{-4}{7}\)
\(=\frac{1}{9}.\frac{-4}{7}\)
\(=\frac{-4}{63}\)
c) \(-63,99-\left(\frac{4}{9}-63,99\right)-\left(-1\frac{2}{3}\right)^2\)
\(=-63,99-\frac{4}{9}+63,99-\left(\frac{-5}{3}\right)^2\)
\(=-63,99-\frac{4}{9}+63,99-\frac{25}{9}\)
\(=\left(-63,99+63,99\right)-\left(\frac{4}{9}+\frac{25}{9}\right)\)
\(=-\frac{29}{9}\)
giúp tớ với
Câu 1:
a) \(=\frac{42}{5}:\frac{14}{5}\)
\(=3\)
b)
\(=15-\frac{7}{3}:\left(\frac{4}{9}-\frac{1}{6}\right)\)
\(=15-\frac{7}{3}:\frac{4}{9}+\frac{7}{3}:\frac{1}{6}\)
\(=15-\frac{21}{4}+14\)
\(=29-\frac{21}{4}=29-5-\frac{1}{4}\)
\(=24-\frac{1}{4}=\frac{95}{4}\)