A, 70 - 5 . ( x - 3 ) = 45

          5.( x - 3 )    = 70 - 45

          5. ( x - 3 )  = 25

                x - 3    = 25 : 5

                x  - 3    = 5

                     x     = 5 + 3 

                     x = 8

B, 5^{2x - 3} - 2.5² = 5².3

   5^{2x - 3}   - 2.25 = 25.3

   5^{2x - 3}   - 50    = 75

  5^{2x - 3}             = 75 + 50

  5^{2x - 3}                = 125

   5^{2x - 3}               = 5³

      2x - 3          = 3

        2x             = 3 + 3 

        2x             = 6

           x            = 6 : 2 

             x          = 3

Ta có: \(\left(\frac{2}{5}\right)^x>\left(\frac{2}{5}\right)^3\cdot\left(-\frac{2}{5}\right)^2\)

\(\Leftrightarrow\left(\frac{2}{5}\right)^x>\left(\frac{2}{5}\right)^3\cdot\left(\frac{2}{5}\right)^2\)

\(\Leftrightarrow\left(\frac{2}{5}\right)^x>\left(\frac{2}{5}\right)^5\)

\(\Leftrightarrow x< 5\)

Vậy x < 5

\(\Leftrightarrow\left(2x+3-2x+5\right)^2=x^2+6x+64\)

=>x^2+6x=0

=>x(x+6)=0

=>x=0 hoặc x=-6

 20 . 2^x + 1 = 10.4^2 + 1 

 20 . 2^x + 1 = 10 . 16 + 1

20 . 2^x + 1 = 161

20 . 2^x = 161 - 1

20 . 2^x = 160

2^x = 8

2^x = 2^3

=> x = 3

Ban co giai dc phan 2 ko ?

\(\dfrac{5}{6}-\dfrac{1}{2}\left(x-\dfrac{1}{3}\right)-\dfrac{2}{5}x=0\Rightarrow\dfrac{1}{2}\left(x-\dfrac{1}{3}\right)-\dfrac{2}{5}x=\dfrac{5}{6}\)

\(\Rightarrow\dfrac{1}{2}x-\dfrac{1}{6}-\dfrac{2}{5}x=\dfrac{5}{6}\Rightarrow\dfrac{1}{2}x-\dfrac{2}{5}x=\dfrac{5}{6}+\dfrac{1}{6}=1\)

\(\Rightarrow x\left(\dfrac{1}{2}-\dfrac{2}{5}\right)=1\Rightarrow\dfrac{1}{10}x=1\Rightarrow x=1:\dfrac{1}{10}=10\)

Vậy x = 10

mình không biết cách làm, nhưng mình biết x = 7,5

\(4x-3-x-5-=x+2-2x+2.10\)

\(3x-8=x+2-2x+20\)

\(3x=x+10-2x+20\)

\(3x=-x+30\)

\(4x=30\)

\(x=\frac{30}{4}=7,5\)