Tính

a, \(\frac{\left(\frac{1}{6}\right)^2.6^2+\left(0,6\right)^5}{\left(0,2\right)^5}\)

b,  \(\left(-3\right)^2+\left(\frac{-1}{2}\right)^3-\left(3,5\right)^0\)

c, \(2\frac{1}{4}+\frac{2}{5}.0,3-\left(\frac{12}{5}-3\right)^2\)

Tính 

a, \(\frac{2^5.8^4.4^3}{16^6}\)

b, \(\frac{\left(\frac{1}{6}\right)^2.6^2+\left(0,6\right)^5}{\left(0,2\right)^5}\)

c, \(\left(\frac{3}{5}-\frac{3}{4}\right).\left(\frac{2}{6}-\frac{1}{5}\right)^2\)

d, \(\frac{8^4.3^6}{2^7.65}\)

e, \(\frac{2^5.49^2}{4^3.7^3}\)

Thực hiện phép tính

c) \(\left[\left(\frac{4}{3}\right)^{-3}\left(\frac{3}{4}\right)^6\right]:\left(\frac{3}{2}\right)^6\)

d)\(\left[\left(-\frac{1}{2}\right)^3-\left(\frac{3}{4}\right)^3\left(-2\right)^2\right]:\left[2\left(-1\right)^5+\left(\frac{3}{4}\right)^2-\frac{3}{8}\right]\)

Tính

a, \(\frac{2^5.8^4.4^3}{16^6}\)

b, \(\frac{\left(\frac{1}{6}\right)^2.6^2+\left(0,6\right)^5}{\left(0,2\right)^5}\)

c, \(\left(\frac{3}{5}-\frac{3}{4}\right).\left(\frac{2}{6}-\frac{1}{5}\right)^2\)

d, \(\frac{8^4.3^6}{2^7.65}\)

e, \(\frac{2^5.49^2}{4^3.7^3}\)

Thực hiện phép tính

a) \(\left[6.\left(-\frac{1}{3}\right)^2-3.\left(-\frac{1}{3}\right)+1\right]:\left(-\frac{1}{3}-1\right)\)

b) \(\frac{\left(\frac{2}{3}\right)^3.\left(-\frac{3}{4}\right)^2.\left(-1\right)^{2003}}{\left(\frac{2}{5}\right)^2.\left(-\frac{5}{12}\right)^3}\)

Thực hiện phép tính:

a) A=\(\left(-\frac{3}{4}+\frac{2}{3}\right):\frac{5}{11}\)                    b)B=\(\left(-\frac{2}{3}+1\right)-\left(\frac{7}{5}-0,2\right)+\left(\frac{7}{15}-1+\frac{4}{3}\right)\)

c) C=\(\frac{^{^{2^4.2^6}}}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)

Tính:

a)\(\left\{\left[\left(6,2:0,31-\frac{5}{6}.0,9\right).0,2+0,15\right]:0,2\right\}:\left[\left(2+1\frac{4}{11}:0,1\right).\frac{1}{33}\right]\)

b)\(0,4\left(3\right)+0,6\left(2\right)-2\frac{1}{2}.\left[\left(\frac{1}{2}+\frac{1}{3}:0,5\left(8\right)\right)\right]:\frac{50}{53}\)

c)\(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}\)

Thực hiện phép tính theo cách hợp lí :

a, \([6.\left(-\frac{1}{3}\right)^2-3.\left(-\frac{1}{3}\right)+1]:\left(-\frac{1}{3}-1\right)\)

b, \(\frac{\left(\frac{2}{3}\right)^3.\left(-\frac{3}{4}\right)^2.\left(-1\right)^{2003}}{\left(\frac{2}{5}\right)^2.\left(-\frac{5}{12}\right)^3}\)

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