1-5x/2=13/36-x+1/3
Giải giúp mik vs nhé
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a. x + \(\dfrac{3}{7}\)= \(\dfrac{2}{5}:\dfrac{18}{25}=>x+\dfrac{3}{7}=\dfrac{2}{5}\)x\(\dfrac{35}{18}=>x+\dfrac{3}{7}=\dfrac{7}{9}\)
=> x = \(\dfrac{7}{9}-\dfrac{3}{7}=\dfrac{49}{63}-\dfrac{27}{63}=\dfrac{22}{63}\)
b. \(x\) x \(\dfrac{5}{9}\)= \(\dfrac{4}{5}-\dfrac{1}{3}\)
=> \(x\) x \(\dfrac{5}{9}\)= \(\dfrac{12}{15}-\dfrac{5}{15}=>x\) x \(\dfrac{5}{9}\)= \(\dfrac{7}{15}\)
=> x = \(\dfrac{7}{15}:\dfrac{5}{9}\)
=> x = \(\dfrac{21}{25}\)
\(a.x+\dfrac{3}{7}=\dfrac{2}{5}:\dfrac{18}{35}\\x+\dfrac{3}{7}=\dfrac{2}{5}\times\dfrac{35}{18} \\ x+\dfrac{3}{7}=\dfrac{7}{9}\\ x=\dfrac{7}{9}-\dfrac{3}{7}\\ x=\dfrac{22}{63}\)
\(b.x\times\dfrac{5}{9}=\dfrac{4}{5}-\dfrac{1}{3}\\x\times\dfrac{5}{9}=\dfrac{7}{15}\\ x=\dfrac{7}{15}:\dfrac{5}{9}\\ x= \dfrac{21}{25}\)
\(\dfrac{4x+3}{5}-\dfrac{6x-2}{7}-\dfrac{5x+4}{3}>3\)
=>4/5x+3/5-6/7x+2/7-5/3x-4/3>3
=>-181/105x>362/105
=>x<-2
Ta có: |-2x +1| = -2x+1 khi -2x+1 ≥ 0 hay x ≤ \(\dfrac{1}{2}\)
|-2x +1| = - ( -2x+1) = 2x-1 khi -2x +1 < 0 hay x > \(\dfrac{1}{2}\)
Với x ≤ \(\dfrac{1}{2}\) ta có phương trình:
-2x+1 = x + 3
-2x - x = 3 - 1
-3x = 2
x = \(\dfrac{-2}{3}\) ( nhận)
Với x > \(\dfrac{1}{2}\) ta có phương trình:
2x-1 = x + 3
2x - x = 3+1
x = 4 (nhận)
Vậy phương trình có tập nghiệm S = {\(\dfrac{-2}{3};\) 4 }
a, Thay x = 3 và y = -6 vào bt ta đc
\(5.3-4.\left(-6\right)=15-\left(-24\right)=39\\ b,\\ 2.\left(-2\right)^2-5.4=8-20=\left(-12\right)\\ c,\\ 5.\left(-1\right)^2+3.\left(-1\right)-1=5+\left(-3\right)-1=1\)
a) Thay x=3; y=-6
\(5x-4y=5.3-4.\left(-6\right)=15+24=39\)
b) Thay x=-2; y=4
\(2x^4-5y=2.\left(-2\right)^4-5.4=32-20=12\)
c, Thay x=0
\(5x^2+3x-1=5.0+3.0-1=-1\)
+) x=-1
\(5x^2+3x-1=5.\left(-1\right)^2+3.\left(-1\right)-1=5-3-1=1\)
+) \(x=\dfrac{1}{3}\)
\(5x^2+3x-1=5.\left(\dfrac{1}{3}\right)^2+3.\dfrac{1}{3}-1\)
\(=\dfrac{5}{9}+1-1=\dfrac{5}{9}\)
36 x ( 10 + 1 )
= 36 x 11
= 396
36 x 10 + 36 x 1
= 360 + 36
= 396
Cách 1 :
36 x ( 10 + 1 )
= 36 x 11
= 396
Cách 2 :
36 x ( 10 + 1 )
= 36 x 10 + 36 x 1
= 360 + 36
= 396
a) 1/2.x+3/5.(x-2)=3
<=>1/2.x+3/5.x-6/5=3
<=>11/10.x-6/5=3
<=>11/10x=41/10
<=>x=41/11
b) (3x-4).(5x+15)=0
<=>3x-4=0 hoặc 5x+15=0
<=>x=4/3 hoặc x=-3
\(-\dfrac{1}{2}x+6< 0\Leftrightarrow-\dfrac{1}{2}x< -6\Leftrightarrow\cdot\dfrac{1}{2}x>6\Leftrightarrow x>12\)
(sai thì thoi nha)
\(-\dfrac{1}{2}x+6< 0\)
\(\Leftrightarrow-\dfrac{1}{2}x< -6\)
\(\Leftrightarrow x>\left(-6\right):\left(-\dfrac{1}{2}\right)\)
\(\Leftrightarrow x>12\)
--> Chọn A
\(1-\frac{5x}{2}=\frac{13}{36}-x+\frac{1}{3}\)
\(\Leftrightarrow\frac{2-5x}{2}=\frac{13}{36}-\frac{36x}{36}+\frac{12}{36}\)
\(\Leftrightarrow\frac{36-60x}{36}=\frac{13-36x+12}{36}\Leftrightarrow36-60x=13-36x+12\)
\(\Leftrightarrow11-24x=0\Leftrightarrow x=\frac{11}{24}\)