124 x 25 + 24 x 124 + 50 + 124

= 124 x 25 + 50 ( 24 + 1 )

= 124 x ( 25 + 50 + 25 )

= 124 x 100

= 124000

Nhìn mà mún lòi cả con mắt hà

1,x=-282                                                                                                                       b,x=-1800                                                                                                                 c,x=-24

(14678:2+2476)*(2576-2575)

=9815*1

=9815

(195-13*15):(1954+1014)

=(195-195):2959

=0:2959

=0

(14678:2+2476)x(2576-2575)

=(7339+2476)x1

=9815x1

=9815

(195-13x15):(1954+1014)

=(195-195):(1954+1014)

=0:(1954+1014)

=0

\(a,\left|2x-5\right|=1\)

\(\Rightarrow\orbr{\begin{cases}2x-5=1\\2x-5=-1\end{cases}\Rightarrow\orbr{\begin{cases}2x=6\\2x=4\end{cases}\Rightarrow}\orbr{\begin{cases}x=3\\x=2\end{cases}}}\)

b, đề thiếu 

À ý b, thiếu : [124-920-4x)]:30+7=11 như này là đề đúng

  124 : 0,25 + 6 x 124 

= 124 : \(\frac{25}{100}\)+ 6 x 124

= 124 x \(\frac{100}{25}\)+ 6 x 124

= 124 x 4 + 6 x 124

= 124 x ( 4 + 6 )

= 124 x 10 

= 1240

124x4+6x124

124x(6+4)

124x10

1240

1,

a, \(x\)x 124= 4829-365

 \(x\)x 124 = 4464

\(x\)= 4464 :124

\(x\)= 36.

b,\(x\)x 137 = 25 x 3 

   \(x\)x 137 = 75

\(x\)= \(\frac{75}{137}\)

2,

\(\frac{4}{5}\)x\(\frac{3}{7}+\frac{4}{5}\)x\(\frac{6}{7}-\frac{4}{5}\)x\(\frac{4}{10}\)

=\(\frac{4}{5}\)x\(\left(\frac{3}{7}+\frac{6}{7}-\frac{4}{10}\right)\)=\(\frac{4}{5}\)x\(\frac{31}{35}\)\(\frac{124}{175}\)

\(\text{Bài }1\text{ : Tìm }x\text{ : }\)

\(a,\text{ }x\text{ x }124=4829-365\)

     \(x\text{ x }124=4464\)

     \(x=4464\text{ : }124\)

     \(x=36\)

\(b,\text{ }x\text{ x }137=25\text{ x }3\)

     \(x\text{ x }137=75\)

     \(x=75\text{ : }137\)

     \(x=\frac{75}{137}\)

\(\text{Bài }2\text{ : Tính bằng cách thuận tiện nhất : }\)

      \(\frac{4}{5}\text{ x }\frac{3}{7}+\frac{4}{5}\text{ x }\frac{6}{7}-\frac{4}{5}\text{ x }\frac{4}{10}\)

\(=\frac{4}{5}\text{ x }\left(\frac{3}{7}+\frac{6}{7}-\frac{4}{10}\right)\)

\(=\frac{4}{5}\text{ x }\left(\frac{9}{7}-\frac{4}{10}\right)\)

\(=\frac{4}{5}\text{ x }\frac{31}{35}\)

\(=\frac{124}{175}\)

\(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}\)\(=3\)

\(\Leftrightarrow\frac{x-152}{2011}+\frac{x-2135}{28}+\frac{x-2039}{124}=3\)\(\Leftrightarrow\left(\frac{x-152}{2011}-1\right)+\left(\frac{x-2135}{28}-1\right)+\left(\frac{x-2039}{124}-1\right)=3-1-1-1\)

\(\Leftrightarrow\frac{x-2163}{2011}+\frac{x-2163}{28}+\frac{x-2163}{124}=0\)

\(\Leftrightarrow\left(x-2163\right)\left(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\right)=0\)

        Vì \(\left(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\right)>0\)

  \(\Rightarrow x-2163=0\)

\(\Leftrightarrow x=2163\)

          Vậy \(x=2163\)

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