\(3^3\cdot5^3-20\cdot\left\{300-\left[546-2^3\cdot\left(7^8-7^6+7^0\right)\right]\right\}\)

\(=3^3\cdot5^3-20\cdot\left\{300-\left[546-2^3\cdot5647153\right]\right\}\)

\(=3^3\cdot5^3-20\cdot\left\{300-\left[546-45177224\right]\right\}\)

\(=3^3\cdot5^3-20\cdot\left\{300--45176678\right\}\)

\(=3^3\cdot5^3-20\cdot45176978\)

\(=3375-903539560\)

\(=-903536185\)

\(626500:\left\{50^2:\left[178-4\cdot\left(35-21:3\right)\right]\right\}\)

\(=626500:\left\{50^2:\left[178-4\cdot\left(35-7\right)\right]\right\}\)

\(=626500:\left\{50^2:\left[178-4\cdot28\right]\right\}\)

\(=626500:\left\{50^2:\left[178-112\right]\right\}\)

\(=626500:\left\{50^2:66\right\}\)

\(=626500:\frac{1250}{33}\)

\(=\frac{82698}{5}\)

CHUC BAN HOC TOT >.<

3² . 5³ - 20{300 - [540 - 2³ (7⁸ : 7⁶ + 7⁰)]}

= 9 . 125 - 20{300 - [540 - 8(7² + 7⁰)]}

= 9 . 125 - 20{300 - [540 - 8(49 + 1)]

= 9 . 125 - 20{300 - [540 - 8.50]

= 9 . 125 - 20{300 - [540 - 400]}

= 9 . 125 - 20{300 - 140}

= 9 . 125 - 20. 160

= 1125 - 3200 = -2075

\(=9\cdot125-20\cdot\left\{300-\left[540-8\cdot\left(7^2+1\right)\right]\right\}\)   

\(=1125-20\cdot\left\{300-\left[540-8\cdot\left(49+1\right)\right]\right\}\)   

\(=1125-20\cdot\left[300-\left(540-8\cdot50\right)\right]\)   

\(=1125-20\cdot\left[300-\left(540-400\right)\right]\)   

\(=1125-20\cdot\left(300-140\right)\)   

\(=1125-20\cdot160\)    

\(=1125-3200\)    

\(=-2075\)

Mn giúp mh với đg cần gấp lắm ln🥺🥺

 3³.5³-20.{300-[540-2³(7⁸:7⁶.7⁰)]}

=27.125-20.{300-[540-8.(49.1)]}

=27.125-20.{300-[540-392]}

=3375-20.{300-148}

=3375-20.152

=3375-3040

=335

tk mk nha. nếu đúng

\(a,\dfrac{2}{5}-\dfrac{3}{8}+\dfrac{7}{6}=\dfrac{16}{40}-\dfrac{15}{40}+\dfrac{7}{6}=\dfrac{1}{40}+\dfrac{7}{6}=\dfrac{3}{120}+\dfrac{140}{120}=\dfrac{143}{120}\)

\(b,\dfrac{2}{3}+\left[\dfrac{5}{7}+\left(-\dfrac{2}{3}\right)\right]=\dfrac{2}{3}+\dfrac{5}{7}+\left(-\dfrac{2}{3}\right)=\left[\dfrac{2}{3}+\left(-\dfrac{2}{3}\right)\right]+\dfrac{5}{7}=0+\dfrac{5}{7}=\dfrac{5}{7}\)

\(c,\dfrac{5}{13}+\left(-\dfrac{5}{7}\right)+\left(-\dfrac{20}{41}\right)+\dfrac{8}{13}+\left(-\dfrac{21}{41}\right)\)

\(=\left(\dfrac{5}{13}+\dfrac{8}{13}\right)-\dfrac{5}{7}-\dfrac{20}{41}-\dfrac{21}{41}=-\dfrac{5}{7}\)

a: =48/120-45/120+140/120

=143/120

b: =2/3-2/3+5/7=5/7

c: =5/13+8/13-5/7-20/41-21/41

=-5/7

ko xem dc de ban oi :/

1) 5 + (-4) = 1

2) (-8) + 2 = -6

3) 8 + (-2) = 6

4) 11 + (-3) = 8

5) (-11) + 2 = -9

6) (-7) + 3 = -4

7) (-5) + 5 = 0

8) 11 + (-12) = -1

9) (-18) + 20 = 2

10) (15) + (-12) = 3

11) (-17) + 17 = 0

12) 16 + (-2) = 14

13) (30) + (-14) = 16

14) (-19) + 20 = 1

15) (-18) + 15 = -3

16) (10) + (-6) = 4

17) (-28) + 14 = -14

18) 15 + (-30) = -15

19) (15) + (-4) = 11

20) (-21) + 11 = -10

21) 8 + (-22) = -14

22) (-15) + 4 = -11

23) (-3) + 2 = -1

24) 17 + (-14) = 3

25) 17 + (-14) = 3

thế này đọc đc mới đỉnh

\(-4872-\left(375-4872\right)+300\)

\(=-4872-375+4872+300\)

\(=-75\)

a) A = -6 . ( -8 + 5 - 4 ) : 3 - 7 . |-2| . 3

    A = -6 . ( -3 - 4 ) : 3 - 7 . 2 . 3

    A = -6 . ( -7 ) : 3 - 14 . 3

    A = 42 : 3 - 42

    A = 14 - 42

    A = -28

Vậy A = -28

b) -4872 - ( 375 - 4872) + 300

= -4872 - 375 + 4872 + 300

= ( -4872 + 4872 ) - ( 375 - 300 )

= 0 - 75

= -75

C