\(\dfrac{-11}{-55}=\dfrac{-11:\left(-11\right)}{\left(-55\right):\left(-11\right)}=\dfrac{1}{5}\\ \dfrac{3}{-11}=\dfrac{3:\left(-1\right)}{-11:\left(-1\right)}=\dfrac{-3}{11}\\ \dfrac{-7}{-33}=\dfrac{-7:\left(-1\right)}{-33:\left(-1\right)}=\dfrac{7}{33}\\ \dfrac{41}{-47}=\dfrac{41:\left(-1\right)}{-47:\left(-1\right)}=\dfrac{-41}{47}\)

\(\dfrac{-11}{-55}=\dfrac{1}{5}\)

\(\dfrac{3}{-11}=\dfrac{-3}{11}\)

\(\dfrac{-7}{-33}=\dfrac{7}{33}\)

\(\dfrac{41}{-47}=\dfrac{-41}{47}\)

Theo tính chất cơ bản của phân số, ta có:

\(\dfrac{8}{{ - 11}} = \dfrac{{8.\left( { - 1} \right)}}{{\left( { - 11} \right).\left( { - 1} \right)}} = \dfrac{{ - 8}}{{11}}\)

\(\dfrac{-5}{{ - 9}} = \dfrac{{-5.\left( { - 1} \right)}}{{\left( { - 9} \right).\left( { - 1} \right)}} = \dfrac{{ 5}}{{9}}\)

\(\frac{3}{-4}=\frac{3.-1}{-4.-1}=\frac{-3}{4}\)

\(\frac{-5}{-7}=\frac{-5.-2}{-7.-2}=\frac{10}{14}\)

\(\frac{2}{-9}=\frac{2.-3}{-9.-3}=\frac{-6}{27}\)

\(\frac{-11}{-10}=\frac{-11.-2}{-10.-2}=\frac{22}{20}\)

#H

lỗi r bn

lỗi hoài

a)\(\frac{2}{-7}=\frac{-2}{7}\)

b) \(\frac{-3}{-11}=\frac{3}{11}\)

c) \(\frac{6}{-29}=\frac{-6}{29}\)

d) \(\frac{0}{-14}=\frac{0}{14}\)

a)-2/7      b)3/11     c)-6/29      d)0