\(-\frac{3}{5}.\frac{11}{7}+\frac{3}{-5}.\frac{4}{7}+\frac{23}{7}\)

\(=\frac{-3}{5}\left(\frac{11}{7}+\frac{4}{7}\right)+\frac{23}{7}\)

\(=\frac{-3}{5}.\frac{15}{7}+\frac{23}{7}\)

\(=\frac{-9}{7}+\frac{23}{7}=2\)

`a)3/5+(-4/9)`

`=3/5-4/9`

`=27/45-20/45`

`=7/45`

`b)3/5+2/5 . 15/8`

`=3/5 + 30/40`

`=3/5+3/4`

`=12/20+15/20`

`=27/20`

`c)7/2 . 8/13 + 8/13 . (-5/2)`

`=8/13 . (7/2 +(-5)/2)`

`=8/13 . 1`

`=8/13`

`d)-5/17 . (-9/23)+9/23 . (-22/17) + 11 9/23`

`=-5/17 . (-9/23) + 9/23 . (-1) . 22/17 + 11 + 9/23`

`=-5/17 . (-9/23) + (-9/23) . 22/17+11+9/23`

`= -9/23 ( -5/17 + 22/17)+11+9/23`

`= - 9/23 . 1+11+9/23`

`=-9/23+11+9/23`

`=(-9/23+9/23)+11`

`=0+11`

`=11`

a: =27/45-20/45=7/45

b: =3/5+30/40

=3/5+3/4

=12/20+15/20

=27/20

c: =8/13(7/2-5/2+1)=8/13*2=16/13

d: =9/23*5/17-9/23*22/17+11+9/23

=-9/23+11+9/23

=11

\(\Rightarrow A=\left(\frac{27}{23}-\frac{4}{23}\right)+\left(\frac{5}{21}+\frac{16}{21}\right)+\frac{1}{2}\)

\(\Rightarrow A=1+1+\frac{1}{2}\)

\(\Rightarrow A=\frac{5}{2}\)

tíc mình nha

A=1+1+1/2

A=5/2

a, 64 . 23 + 37 . 23  - 23 

= 23. (64 + 37  - 1) 

= 23 . 100

=2300 

b, 33,76 + 19,52 + 6,24 

= (33,76 + 6,24) + 19,52 

= 40 + 19,52 

= 59,52 

c, 38/11 + (16/13 + 6/11) 

 = 38/11 + 16/13 + 6/11 

= (38/11 + 6/11) + 16/13 

= 4 + 16/13 

= 52/13 + 16/13 

= 68/13 

d, 3/4 : 3/5 - 1/5 

= 3/4 . 5/3 - 1/5 

= 5/4 - 1/5 

= 25/20 - 4/20 

= 21/20

e, \(5\frac{3}{4}\div\frac{12}{13}+6\frac{1}{4}\div\frac{12}{13}\)

\(=\frac{23}{4}\cdot\frac{13}{12}+\frac{25}{4}\cdot\frac{13}{12}\)

\(=\frac{13}{12}\cdot\left(\frac{23}{4}+\frac{25}{4}\right)\)

\(=\frac{13}{12}\cdot12=13\)

f, S = 1 + 2 + 3 + 4 + ... + 99 + 100 

Số số hạng của S là : 

(100 - 1) : 1 + 1 = 100 (số hạng) 

Tổng của S là : 

(1 + 100) . 100 : 2 = 5050

Vậy S = 5050 

Dấu " . " là dấu nhân nhé :D 

\(=\dfrac{9}{23}\left(\dfrac{5}{17}-\dfrac{22}{17}\right)+11+\dfrac{9}{23}=11\)

câu C đề sai hay sao í

a)=(4.25).37

    =100.37

    =3700

b)=(132+868)+(763+237)+29

   =1000+1000+29

   =2029

c)=7²+[131-1.20]

  =49+[131-20]

  =49+111

  =160