a: =35/11-13/11-7/13-6/13

=2-1=1

b: =2+1/7+6/7+7/9-25/9

=2+1-2=1

c: \(=\dfrac{132}{321}\left(-\dfrac{103}{13}-\dfrac{27}{13}\right)=\dfrac{-132}{321}\cdot10=-\dfrac{440}{107}\)

lần sau viết cẩn thận hơn một xíu xiu xìu xiu nx thui là chuẩn đứa nèo chỉnh tát vỡ đôi mồm

2:

a: x+201=351

=>x=351-201

=>x=150

b: \(8\cdot5^2-27:25\)

\(=8\cdot25-\dfrac{27}{25}\)

\(=200-1,08=198,92\)

d: \(2023-23:\left[9+2\left(2^3-0,21\right)\right]\)

\(=2023-23:\left[9+16-0,42\right]\)
\(=2023-\dfrac{23}{25-0,42}\)

\(=2023-\dfrac{1150}{1229}=\dfrac{2485117}{1229}\)

b: 2(x-21)=84

=>x-21=84/2=42

=>x=42+21=63

c: 135-4(81-x)=55

=>4(81-x)=135-55=80

=>81-x=20

=>x=61

a)

\(\begin{array}{l}2023 - {25^2}:{5^3} + 27\\ = 2023 - {5^4}:{5^3} + 27\\ = 2023 - 5^{4-3} + 27\\ = 2023 -5 + 27\\ =2018+27\\= 2045\end{array}\)

b)

\(\begin{array}{l}60:\left[ {7.\left( {{{11}^2} - 20.6} \right) + 5} \right]\\ = 60:\left[ {7.\left( {121 - 120} \right) + 5} \right]\\ = 60:\left[ {7.1 + 5} \right]\\ = 60:12\\ = 5\end{array}\)

a. (7-3+1)/8 = 5/8

b. (-5+26-1)/21 = 20/21

c. (-3-8+5)/27 = -6/27= -2/9

a: \(\dfrac{1}{8}\cdot\dfrac{4}{5}:\dfrac{3}{5}=\dfrac{1}{10}\cdot\dfrac{5}{3}=\dfrac{1}{2\cdot3}=\dfrac{1}{6}\)

b: \(=\dfrac{8-3}{12}\cdot\dfrac{6}{5}=\dfrac{6}{12}=\dfrac{1}{2}\)

c: \(=\dfrac{24}{35}:\dfrac{32}{35}=\dfrac{3}{4}\)

d: =63/21+15/21-7/21=71/21

a \(\dfrac{1}{8}\times\dfrac{4}{5}\times\dfrac{10}{6}=\dfrac{1}{6}\)

b \(\left(\dfrac{8}{12}-\dfrac{3}{12}\right)\times\dfrac{6}{5}=\dfrac{5}{12}\times\dfrac{6}{5}=\dfrac{1}{2}\)

c \(\dfrac{24}{35}:\dfrac{32}{35}=\dfrac{24}{35}\times\dfrac{35}{32}=\dfrac{3}{4}\)

d \(\dfrac{63}{21}+\dfrac{15}{21}-\dfrac{7}{21}=\dfrac{71}{21}\)

\(\dfrac{2}{3}+\dfrac{1}{5}.\dfrac{10}{7}=\dfrac{2}{3}+\dfrac{10}{35}=\dfrac{70}{105}+\dfrac{30}{105}=\dfrac{100}{105}=\dfrac{50}{21}\)

a) Ta có: \(\dfrac{2}{3}+\dfrac{1}{5}\cdot\dfrac{10}{7}\)

\(=\dfrac{2}{3}+\dfrac{2}{7}\)

\(=\dfrac{14}{21}+\dfrac{6}{21}\)

\(=\dfrac{20}{21}\)

a) 600000

c) -40

e) 1922

b) -35

d) 350

cách làm đi bạn

a: \(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\left(1+5\right)}=\dfrac{-2}{6}=\dfrac{-1}{3}\)

b: \(=\dfrac{5^{16}\cdot3^{21}}{5^{15}\cdot3^{22}}=\dfrac{5}{3}\)