ko hiểu

uk 276 nha mik tính là vậy còn ko biết đúng ko nữa cho mik 1 k nha hihi / HT/

minh biet minh cung tung bi rui k minh minh tra loi cho

đó là do chúng ta chưa có Vip nên vậy đó

a,=(x\(^2\)-6x+9)+10-9

=(x-3)\(^2\)+1

Mà(x-3)\(^2\)\(\ge\)0

nên (x-3)\(^2\)+1>0

b,=  -(-4x+x\(^2\))-5

=    -(4-4x+x\(^2\))-5+4

=     -(2-x)\(^2\)-1

Mà  -(2-x)\(^2\)\(\le\)0

nên -(2-x)\(^2\)-1<   0

Võ Hoàng Tiên: Cảm ơn pạn nhiều lắm =)) nek :3 Hí Hí :)  Thankssssss 

\(2\left(x-5\right)+10=20\)

\(\Leftrightarrow2\left(x-5\right)=10\)

\(\Leftrightarrow x-5=5\)

\(\Leftrightarrow x=10\)

\(\left(3x+1\right)-17=5\)

\(\Leftrightarrow3x+1=22\)

\(\Leftrightarrow3x=21\)

\(\Leftrightarrow x=7\)

\(\left(10x+120\right)-138=262\)

\(\Leftrightarrow10x+120=400\)

\(\Leftrightarrow10x=280\)

\(\Leftrightarrow x=28\)

\(4\left(x+1\right)-12=8\)

\(\Leftrightarrow4\left(x+1\right)=20\)

\(\Leftrightarrow x+1=5\)

\(\Leftrightarrow x=4\)

\(2x+2\frac{1}{3}=\frac{1}{2}:\frac{3}{2}\)

\(\Leftrightarrow2x+\frac{7}{3}=\frac{1}{3}\)

\(\Leftrightarrow2x=-2\)

\(\Leftrightarrow x=-1\)

\(m\left(x\right)+h\left(x\right)=g\left(x\right)-5\)

\(\Leftrightarrow m\left(x\right)=g\left(x\right)-h\left(x\right)-5\)

\(\Leftrightarrow m\left(x\right)=4x^2+3x+1-3x^2+2x+3-5\)

\(\Leftrightarrow m\left(x\right)=x^2+5x-1\)

1/4×2/6×3/8×4/10×...×14/30×15/32=1/2^x

<=>1/(2×2)×2/(2×3)×...×14/(2×15)×15/2^5=1/2^x

<=>1/2×1/2×...×1/2×1/(2^5)=1/2^x

<=>1/2^19=1/2^x=>x=19

Đề mình không ghi lại nhé.

^{\(\Rightarrow\frac{1\times2\times3\times4\times...\times14\times15}{4\times6\times10\times...\times30\times32}=\frac{1}{2^x}\)}\(\frac{1}{2^x}\)

\(\Rightarrow\frac{1\times2\times3\times4\times...\times14\times15}{2\times4\times6\times8\times10\times...\times30\times32}\)\(=\frac{1}{2^{x+1}}\)

\(\Rightarrow\frac{1}{2^{15}\times32}=\)\(\frac{1}{2^{x+1}}\)

\(\Rightarrow2^{15}\times2^5=2^{x+1}\)

\(\Rightarrow2^{20}=2^{x+1}\)

\(\Rightarrow x+1=20\Rightarrow x=19\)

Vậy \(x=1\)

Học tốt nhaaa!

1, \(2x^2+4x=2x\left(x+2\right)\)

2, \(15x^3+5x^2-10x=5x\left(3x^2+x-2\right)=5x\left(x-\dfrac{2}{3}\right)\left(x+1\right)\)

3) \(5x^2\left(x-2y\right)+15x\left(x-2y\right)=\left(5x^2+15x\right)\left(x-2y\right)=5x\left(x+3\right)\left(x-2y\right)\)

4) \(3\left(x-y\right)+5x\left(y-x\right)=\left(x-y\right)\left(3-5x\right)\)

5) \(5x^2-10x=5x\left(x-2\right)\)

6) \(3x-6y=3\left(x-2y\right)\)

7) \(25x^2+5x^3+x^2y=x^2\left(25+5x+y\right)\)

8) \(14x^2y-21xy^2+28x^2y^2=7xy\left(2x-3y+4xy\right)\)

9) \(x\left(y-1\right)-y\left(y-1\right)=\left(x-1\right)\left(y-1\right)\)

10) \(10x\left(x-y\right)-8y\left(y-x\right)=\left(10x+8y\right)\left(x-y\right)=2\left(5x+4y\right)\left(x-y\right)\)

\(1,=2x\left(x+2\right)\\ 2,=5x\left(3x^2+x-2\right)\\ 3,=\left(x-2y\right)\left(5x^2+15x\right)=5x\left(x+3\right)\left(x-2y\right)\\ 4,=\left(x-y\right)\left(3-5x\right)\\ 5,=5x\left(x-2\right)\\ 6,=3\left(x-2y\right)\\ 7,=5x^2\left(5+x+y\right)\\ 8,=7xy\left(2x-3y+4xy\right)\\ 9,=\left(y-1\right)\left(x-y\right)\\ 10,=\left(x-y\right)\left(10x+8y\right)=2\left(5x+4y\right)\left(x-y\right)\)

Em cần bài nào đăng lên 1 bài đó nha