a: \(\dfrac{1}{8}\cdot\dfrac{4}{5}:\dfrac{3}{5}=\dfrac{1}{10}\cdot\dfrac{5}{3}=\dfrac{1}{2\cdot3}=\dfrac{1}{6}\)

b: \(=\dfrac{8-3}{12}\cdot\dfrac{6}{5}=\dfrac{6}{12}=\dfrac{1}{2}\)

c: \(=\dfrac{24}{35}:\dfrac{32}{35}=\dfrac{3}{4}\)

d: =63/21+15/21-7/21=71/21

a \(\dfrac{1}{8}\times\dfrac{4}{5}\times\dfrac{10}{6}=\dfrac{1}{6}\)

b \(\left(\dfrac{8}{12}-\dfrac{3}{12}\right)\times\dfrac{6}{5}=\dfrac{5}{12}\times\dfrac{6}{5}=\dfrac{1}{2}\)

c \(\dfrac{24}{35}:\dfrac{32}{35}=\dfrac{24}{35}\times\dfrac{35}{32}=\dfrac{3}{4}\)

d \(\dfrac{63}{21}+\dfrac{15}{21}-\dfrac{7}{21}=\dfrac{71}{21}\)

b) Ta có: \(5^{x+4}-3\cdot5^{x+3}=2\cdot5^{11}\)

\(\Leftrightarrow2\cdot5^{x+3}=2\cdot5^{11}\)

\(\Leftrightarrow x+3=11\)

hay x=8

c) Ta có: \(2\cdot3^{x+2}+4\cdot3^{x+1}=10\cdot3^6\)

\(\Leftrightarrow18\cdot3^x+12\cdot3^x=10\cdot3^6\)

\(\Leftrightarrow30\cdot3^x=30\cdot3^5\)

Suy ra: x=5

d) Ta có: \(6\cdot8^{x-1}+8^{x+1}=6\cdot8^{19}+8^{21}\)

\(\Leftrightarrow6\cdot\dfrac{8^x}{8}+8^x\cdot8=6\cdot8^{19}+64\cdot8^{19}\)

\(\Leftrightarrow8^x\cdot\dfrac{35}{4}=70\cdot8^{19}\)

\(\Leftrightarrow8^x=8^{20}\)

Suy ra: x=20

8 x 1 = 8        8 x 2 = 16       8 x 3 = 24       8 x 4 = 32

1 x 8 = 8        2 x 8 = 16       3 x 8 = 24       4 x 8 = 32

8 x 5 = 40       8 x 6 = 48       8 x 7 = 56       8 x 8 = 64

5 x 8 = 40       6 x 8 = 48       7 x 8 = 56       8 x 9 = 72

\(a,x+21=6\\ \Rightarrow x=-15\\ b,x-10=-8\\ \Rightarrow x=2\\ c,\left(-8\right)x=\left(-7\right)\left(-6\right)\\ \Rightarrow\left(-8\right)x=42\\ \Rightarrow x=-4\\ d,20+8\left(x+3\right)=5^2.4\\ \Rightarrow20+8\left(x+3\right)=25.4\\ \Rightarrow20+8\left(x+3\right)=100\\ \Rightarrow8\left(x+3\right)=80\\ \Rightarrow x+3=10\\ \Rightarrow x=7\)

\(a.x+21=6\\ x=6-21\\ x=-15\\ b.x-10=-8\\ x=-8+10\\ x=2\\ c.-8x=-7.\left(-6\right)-2\\ -8x=42-2\\ -8x=40\\ x=40:\left(-8\right)\\ x=-5\)

\(d.20+8\left(x+3\right)=5^2.4\\ 20+8x+24=25.4\\ 44+8x=100\\ 8x=100-44\\ 8x=56\\ x=56:8\\ x=7\)

a: =7/8:(2/9-18+1/36)-5/12

=-7/142-5/12=-397/852

b: =3/7(4/9+5/9:6/12)=2/3

c: =5^8(16/31-47/31)+1/3=-5^8+1/3

d: =7/2(3/8+5/8:4/15)=609/64

Cho nên kết quả cau c đi

a, x + \(\dfrac{1}{5}\) = \(\dfrac{5}{6}\)

x = \(\dfrac{5}{6}\) - \(\dfrac{1}{5}\)

x = \(\dfrac{19}{30}\)

b, x - \(\dfrac{3}{5}=\dfrac{6}{7}\)

x = \(\dfrac{6}{7}+\dfrac{3}{5}\)

x = \(1\dfrac{16}{35}\)

c, - x - \(\dfrac{7}{5}=\dfrac{-8}{9}\)

- x = \(\dfrac{-8}{9}+\dfrac{7}{5}\)

x = \(\dfrac{23}{45}\)

d, \(\dfrac{3}{8}-x=\dfrac{2}{3}\)

\(x=\dfrac{3}{8}-\dfrac{2}{3}\)

\(x=\dfrac{-7}{24}\)

e, \(|x-\dfrac{8}{9}|=\dfrac{1}{3}\)

\(x=\dfrac{1}{3}+\dfrac{8}{9}\)

\(x=\dfrac{-11}{9}\)

Hiệu giữa SBT mới và cũ là:

353 – 23 = 330

Hiệu số phần bằng nhau là:

3-1 = 2 phần

Số bị trừ cũ là: 330 : 2 = 165

Số trừ cũ là : 165- 23 = 142

Khó quá nhờ 

Chọn D

Dễ

 Thế

Mà

Cũnhoir

Dc

Ạ

Chịu

Chắc

Phải

Ngu 

Lamqs

Mới

Hỏi

Câu

Này