Tính bằng cách thuận tiện nhất 69,78 +35,97 + 30,22
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69,78 + 35,97 + 30,22 = (69,78 + 30,22) + 35,97=100 + 35,97=135,97
a)69,78 + 35,97 + 30,22
=(69,78+30,22)+35,97
=100 + 35,97
=135,97
b)83,45 - 30,98 - 42,47
=83,45-(30,98+42,47)
=83,45-73,45
=10
\(\frac{72}{99}-\frac{28}{99}-\frac{14}{99}=\frac{72-28-14}{99}\)\(=\frac{30}{99}=\frac{10}{33}\)
\(\left(69,78+30,22\right)+35,97\)\(=100+35,97=135,97\)
\(83,45-\left(30,98+42,47\right)\)\(=83,45-73,45=10\)
72/99-28/99-14/99
=72/99-(28/99+14/99)
=72/99-42/99
=30/99=10/33
67,78+35,97+30,22
=(67,78+30,22)+35,97
=98+35,97
=133,97
83,45-30,98-42,47
=83,45-(30,98+42,47)
=83,45-73,45
=10
a) 7/11+3/4+4/11+1/4
=(7/11+4/11)+(3/4+1/4)
= 1 + 1
= 2.
b) 72/99-28/99-14/99
=72/99-(28/99+14/99)
=72/99- 42/99
= 30/99=10/33.
c) 69,78+35,97+30,22
=(69,78+30,22)+35,97
= 100 +35,97
= 135,97.
d) 83,45-30,98-42,47
=83,45-(30,98+42,47)
=83,45- 73,45
= 10.
a) \(\dfrac{7}{11}+\dfrac{3}{4}+\dfrac{4}{11}+\dfrac{1}{4}=\left(\dfrac{7}{11}+\dfrac{4}{11}\right)+\left(\dfrac{3}{4}+\dfrac{1}{4}\right)=1+1=2\)
b) \(\dfrac{72}{99}-\dfrac{28}{99}-\dfrac{14}{99}=\dfrac{72-28-14}{99}=\dfrac{30}{99}=\dfrac{10}{33}\)
69,78+35,97x3,2:1,5
=1x\(\left(69,78+35,97\right)\)x3,2:1,5
=1x105,75x3,2:1,5
=317,25:1,5
=211,5
7/11 + 3/4 + 4/11 +1/4
= ( 7/11 + 4/11 ) + ( 3/4 + 1/4 )
= 1 + 1
= 2
72/99 - 28/99 - 14/99
= 72/99 - ( 28/99 + 14/99 )
= 72/99 - 42/99
= 50/99
69,78 + 35,97 + 30,22
= ( 69,78 + 30,22 ) + 35,97
= 100 + 35,97
= 135,97
83,45 - 30,98 - 42,47
= 83,45 - ( 30,98 + 42,47 )
= 83,45 - 73,45
= 10
a ) \(\frac{7}{11}+\frac{3}{4}+\frac{4}{11}+\frac{1}{4}\)
\(=\left(\frac{7}{11}+\frac{4}{11}\right)+\left(\frac{3}{4}+\frac{1}{4}\right)\)
\(=\frac{11}{11}+\frac{4}{4}\)
\(=1+1\)
\(=2\)
b ) \(\frac{72}{99}-\frac{28}{99}-\frac{14}{99}\)
\(=\frac{72}{99}-\left(\frac{28}{99}+\frac{14}{99}\right)\)
\(=\frac{72}{99}-\frac{42}{99}\)
\(=\frac{30}{99}\)
c ) \(69,78+35,97+30,22\)
\(=\left(69,78+30,22\right)+35,97\)
\(=100+35,97\)
\(=135,97\)
d ) \(83,45-30,98-42,47\)
\(=83,45-\left(30,98+42,47\right)\)
\(=83,45-73,45\)
\(=10\)
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